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UNCERTAINTY PRINCIPLE
IS
UNTENABLE
By reanalysing the experiment of Heisenberg Gamma-Ray Microscope and one of
ideal experiment from which uncertainty principle is derived , it is found that
actually uncertainty principle can not be obtained from these two ideal
experiments . And it is found that uncertainty principle is untenable.
Key words :
uncertainty principle; experiment of Heisenberg Gamma-Ray Microscope; ideal
experiment
Ideal Experiment 1
Experiment of Heisenberg Gamma-Ray Microscope
A free electron sits directly beneath the center of the microscope's lens
(see the picture below or AIP page:
http://www.aip.org/history/heisenberg/p08b.htm). The circular lens forms a cone
of angle 2A from the electron. The electron is then illuminated from the left by
gamma rays--high energy light which has the shortest wavelength. These yield the
highest resolution, for according to a principle of wave optics, the microscope
can resolve (that is, "see" or distinguish) objects to a size of dx,
which is related to and to the wavelength L of the gamma ray, by the expression:
dx = L/(2sinA) (1)
However, in quantum mechanics, where a light wave can act like a particle, a
gamma ray striking an electron gives it a kick. At the moment the light is
diffracted by the electron into the microscope lens, the electron is thrust to
the right. To be observed by the microscope, the gamma ray must be scattered
into any angle within the cone of angle 2A. In quantum mechanics, the gamma ray
carries momentum, as if it were a particle. The total momentum p is related to
the wavelength by the formula
p = h / L, where h is Planck's constant. (2)
In the extreme case of diffraction of the gamma ray to the right edge of the
lens, the total momentum in the x direction would be the sum of the
electron's momentum P'x in the x direction and the gamma ray's
momentum in the x direction:
P'x + (h sinA) / L', where L' is the wavelength of the
deflected gamma ray.
In the other extreme, the observed gamma ray recoils backward, just hitting the
left edge of the lens. In this case, the total momentum in the x direction is:
P''x - (h sinA) / L''.
The final x momentum in each case must equal the initial x momentum, since
momentum is never lost (it is conserved). Therefore, the final x momenta are
equal to each other:
P'x + (h sinA) / L' = P''x - (h sinA) / L''
(3)
If A is small, then the wavelengths are approximately the same,
L' ~ L" ~ L. So we have
P''x - P'x = dPx ~ 2h sinA / L (4)
Since dx = L/(2 sinA), we obtain a reciprocal relationship between the minimum
uncertainty in the measured position,dx, of the electron along the x axis and
the uncertainty in its momentum, dPx, in the x direction:
dPx ~ h / dx or dPx dx ~ h. (5)
For more than minimum uncertainty, the "greater than" sign may added.
Except for the factor of 4pi and an equal sign, this is Heisenberg's
uncertainty relation for the simultaneous measurement of the position and
momentum of an object
.
Reanalysis
To be seen by the microscope, the gamma ray must be scattered into any angle
within the cone of angle 2A.
The microscope can resolve (that is, "see" or distinguish) objects to
a size of dx, which is related to and to the wavelength L of the gamma ray, by
the expression:
dx = L/(2sinA) (1)
It is the resolving limit of the microscope, and it is the uncertain quantity of
the object's position.
Microscope can not see the object which the size is smaller than its resolving
limit dx.
Therefore, to be seen by the microscope, the size of the electron must be larger
than the resolving limit dx or equal to the resolving limit dx.
But if the size of the electron is larger than or equal to the resolving limit
dx, electron will not be in the range dx. dx can not be deemed to be the
uncertain quantity of the electron's position which can be seen by
microscope, dx can be deemed to be the uncertain quantity of the electron's
position which can not be seen by microscope only.
dx is the position's uncertain quantity of the electron which can not
be seen by microscope
To be seen by the microscope, the gamma ray must be scattered into any angle
within the cone of angle 2A, so we can measure the
momentum of the electron.
dPx is the momentum's uncertain quantity of the electron which can be seen
by microscope.
What relates to dx is the electron which the size is smaller than the
resolving limit .The electron is in the range dx, it can not be seen by the
microscope, so its position is uncertain.
What relates to dPx is the electron which the size is larger than or equal to
the resolving limit .The electron is not in the range dx, it can be seen by the
microscope, so its position is certain.
Therefore, the electron which relate to dx and dPx respectively is not the same.
What we can see is the electron which the size is larger than or equal to the
resolving limit dx and has certain position, dx = 0..
Quantum mechanics does not relate to the size of the object. but on the
Experiment Of Heisenberg Gamma-Ray Microscope, the using of the microscope must
relate to the size of the object, the size of the object which can be seen by
the microscope must be larger than or equal to the resolving limit dx of the
microscope, thus it does not exist alleged the uncertain quantity of the
electron's position dx.
To be seen by the microscope, none but the size of the electron is larger than
or equal to the resolving limit dx, the gamma ray which diffracted by the
electron can be scattered into any angle within the cone of angle 2A, we can
measure the momentum of the electron.
What we can see is the electron which has certain position, dx = 0, so that none
but dx = 0£¬we can measure the momentum of the electron.
In Quantum mechanics, the momentum of the electron can be measured accurately
when we measure the momentum of the electron only, therefore, we can gained dPx
= 0.
Therefore ,
dPx dx =0. (6)
Ideal experiment 2
Experiment of single slit diffraction
Supposing a particle moves in Y direction originally and then passes a slit with
width dx . So the uncertain quantity of the particle position in X direction is
dx (see the picture below) , and interference occurs at the back slit .
According to Wave Optics , the angle where No.1 min of interference pattern is ,
can be calculated by following formula :
sinA=L/2dx (1)
and
L=h/p where h is Planck¡¯s constant. (2)
So uncertainty principle can be obtained
dPx dx ~ h (5)
Reanalysis
According to Newton first law , if the external force at the X direction does
not affect particle ,the particle will keep the uniform straight line Motion
State or Static State , and the motion at the Y direction unchangeable
.Therefore , we can lead its position in the slit form its starting point .
The particle can have the certain position in the slit, and the uncertain
quantity of the position dx =0 .
According to Newton first law , if the external force at the X direction does
not affect particle,and the original motion at the Y direction is unchangeable ,
the momentum of the particle at the X direction will be Px=0 , and the uncertain
quantity of the momentum will be dPx =0.
Get:
dPx dx =0. (6)
It has not any experiment to negate NEWTON FIRST LAW, in spite of quantum
mechanics or classical mechanics, NEWTON FIRST LAW can be the same with the
microcosmic world.
Under the above ideal experiment , it considered that slit¡¯s width is the
uncertain quantity of the particle¡¯s position. But there is no reason for us to
consider that the particle in the above experiment have position¡¯s uncertain
quantity certainly, and no reason for us to consider that the slit¡¯s width is
the uncertain quantity of the particle¡¯s position.
Therefore, uncertainty principle
dPx dx ~ h (5)
which is derived from the above experiment is unreasonable .
Concluson
