I'm working on the post-regalloc dataflow engine I mentioned yesterday. Currently I only need to track register operands. A MachineOperand has both a getReg() and a getSubReg() interface. For a physical register operand, is getReg() guaranteed to be the "most super" register with getSubReg() providing the specific subregister information for the operand? If so then for my current purposes it seems I don't need to worry about subregisters at all. For reaching definitions I think simply tracking definitions via super registers should be sufficient. Even if a definition defines a subregister I can consider it to define the "most super" register. This will be pessimistic for cases like x86 AH/AL, but I hardly care about those at the moment. :) If MachineOperand already tracks the "most super" register then things look pretty simple as far as explicitly defined registers go. Anyone see any problem with this? Thanks! -David
<dag at cray.com> writes:> For reaching definitions I think simply tracking definitions via super > registers should be sufficient. Even if a definition defines a > subregister I can consider it to define the "most super" register. This > will be pessimistic for cases like x86 AH/AL, but I hardly care about > those at the moment. :)I did a big *facepalm* immediately after hitting "Send." If AH and AL come in defined via separate predecessors and the block only defined AH, then AL should remain live through the block. It would be wrong to kill it by considering AH to define RAX. So I do have to track sub/super register explicitly. Not difficult, just a bit more work. -David
<dag at cray.com> writes:> So I do have to track sub/super register explicitly. Not difficult, > just a bit more work.The original question still stands, though. Is the Reg memory of MachineOperand always the "most super" register? -David
On Apr 18, 2013, at 9:45 AM, dag at cray.com wrote:> I'm working on the post-regalloc dataflow engine I mentioned yesterday. > Currently I only need to track register operands. > > A MachineOperand has both a getReg() and a getSubReg() interface. For a > physical register operand, is getReg() guaranteed to be the "most super" > register with getSubReg() providing the specific subregister information > for the operand? If so then for my current purposes it seems I don't > need to worry about subregisters at all.For physregs, getSubReg() is guaranteed to be 0. It is only used for virtual registers.> For reaching definitions I think simply tracking definitions via super > registers should be sufficient. Even if a definition defines a > subregister I can consider it to define the "most super" register. This > will be pessimistic for cases like x86 AH/AL, but I hardly care about > those at the moment. :) If MachineOperand already tracks the "most > super" register then things look pretty simple as far as explicitly > defined registers go. > > Anyone see any problem with this?Yep, there is no such thing as a 'most super' register. The register aliasing graph is not a tree. The graph of sub/super-register relationships is also not a tree, it is a DAG. Take a look at the ARM register bank. It demonstrates most of this stuff. We try to track anything related to register aliasing in terms of register units. See MCRegisterInfo.h and TargetRegisterInfo.h. I believe regunits are equivalent to maximal cliques of the register aliasing graph if you're mathematically inclined. I think it is easier to think about them as minimal sub-registers, even if that is not always completely accurate. /jakob
Jakob Stoklund Olesen <stoklund at 2pi.dk> writes:>> A MachineOperand has both a getReg() and a getSubReg() interface. >> For a physical register operand, is getReg() guaranteed to be the >> "most super" register with getSubReg() providing the specific >> subregister information for the operand? If so then for my current >> purposes it seems I don't need to worry about subregisters at all. > > For physregs, getSubReg() is guaranteed to be 0. It is only used for > virtual registers.Aha! So for physregs, getSubReg() will simply be the exact physical register defined. Cool, that'll work.> Yep, there is no such thing as a 'most super' register. The register > aliasing graph is not a tree. The graph of sub/super-register > relationships is also not a tree, it is a DAG.Hmm. I don't doubt it but can you give me an example of a case where there is no "most super" register? I'm having a hard time thinking up how one would design such an ISA. Need to increase my edjimucation.> We try to track anything related to register aliasing in terms of > register units. See MCRegisterInfo.h and TargetRegisterInfo.h. I > believe regunits are equivalent to maximal cliques of the register > aliasing graph if you're mathematically inclined.Ok, I'll check that out. MCRegisterInfo.h is new to me.> I think it is easier to think about them as minimal sub-registers, > even if that is not always completely accurate.I'm not completely sure what you mean here. Thanks for your help Jakob! -David
Seemingly Similar Threads
- [LLVMdev] MachineOperand SubReg
- [LLVMdev] MachineOperand SubReg
- [LLVMdev] MachineOperand SubReg
- [LLVMdev] [llvm-commits] [llvm] r162770 - in /llvm/trunk: include/llvm/CodeGen/MachineOperand.h lib/CodeGen/MachineInstr.cpp
- [LLVMdev] [llvm-commits] [llvm] r162770 - in /llvm/trunk: include/llvm/CodeGen/MachineOperand.h lib/CodeGen/MachineInstr.cpp