Hi Dennis,
No problem.
As I mentioned, I was under the understanding that "electrode1" occurs
only in multiples of 3.? I think your earlier post sounded like that.? May be I
was misunderstood.? So, my solution was based on that.? In the below table, I am
not sure, how you wanted to split.? For ex. it is not clear, whether rows 1-5
(electrode1) are only in the first list element or should it include? the next
electrode "electrode2" also?? Could you also show the expected output?
dat$Len
# [1]? 5? 4? 5? 3? 5? 6? 4? 5? 4? 3? 4? 6? 3? 5? 3? 4? 3 12? 5? 6? 4? 6? 3
?as.character(dat$Val)
# [1] "electrode1" "electrode2" "electrode1"
"electrode3" "electrode1"
?#[6] "electrode4" "electrode2" "electrode1"
"electrode2" "electrode3"
#[11] "electrode2" "electrode4" "electrode3"
"electrode1" "electrode3"
#[16] "electrode2" "electrode3" "electrode4"
"electrode1" "electrode4"
#[21] "electrode2" "electrode4" "electrode3"
A.K.
Hi Rui & Arun,
really thanks for investing so much time to deal with this problem!
The code works now for this specific example. However it is not
generally robust for slightly different situations. For instance it
cannot correctly handle a slight variation of the table where I have
again 4 types of electrodes of certain lengths. Electrode4 exists only 6
times. At the transition of the combinations 3-4 and 4-1 there are 12
times electrode4 which stick together in the output $`9`. This leads to
wrong splittings thereafter. Sorry for asking such tricky questions.
New table XXX
electrode length
electrode1 206
electrode1 194
electrode1 182
electrode1 172
electrode1 169
electrode2 82
electrode2 78
electrode2 70
electrode2 58
electrode1 206
electrode1 194
electrode1 182
electrode1 172
electrode1 169
electrode3 260
electrode3 176
electrode3 137
electrode1 206
electrode1 194
electrode1 182
electrode1 172
electrode1 169
electrode4 86
electrode4 66
electrode4 64
electrode4 52
electrode4 27
electrode4 26
electrode2 82
electrode2 78
electrode2 70
electrode2 58
electrode1 206
electrode1 194
electrode1 182
electrode1 172
electrode1 169
electrode2 82
electrode2 78
electrode2 70
electrode2 58
electrode3 260
electrode3 176
electrode3 137
electrode2 82
electrode2 78
electrode2 70
electrode2 58
electrode4 86
electrode4 66
electrode4 64
electrode4 52
electrode4 27
electrode4 26
electrode3 260
electrode3 176
electrode3 137
electrode1 206
electrode1 194
electrode1 182
electrode1 172
electrode1 169
electrode3 260
electrode3 176
electrode3 137
electrode2 82
electrode2 78
electrode2 70
electrode2 58
electrode3 260
electrode3 176
electrode3 137
electrode4 86
electrode4 66
electrode4 64
electrode4 52
electrode4 27
electrode4 26
electrode4 86
electrode4 66
electrode4 64
electrode4 52
electrode4 27
electrode4 26
electrode1 206
electrode1 194
electrode1 182
electrode1 172
electrode1 169
electrode4 86
electrode4 66
electrode4 64
electrode4 52
electrode4 27
electrode4 26
electrode2 82
electrode2 78
electrode2 70
electrode2 58
electrode4 86
electrode4 66
electrode4 64
electrode4 52
electrode4 27
electrode4 26
electrode3 260
electrode3 176
electrode3 137
----- Original Message -----
From: arun <smartpink111 at yahoo.com>
To: "dennis1991 at gmx.net" <dennis1991 at gmx.net>
Cc:
Sent: Friday, July 26, 2013 1:05 AM
Subject: Re: [R] How to split two levels several times?
Just to add:
I assumed that "electrode1" would be found in multiples of 3.? I could
be wrong.?
----- Original Message -----
From: arun <smartpink111 at yahoo.com>
To: Rui Barradas <ruipbarradas at sapo.pt>
Cc: "dennis1991 at gmx.net" <dennis1991 at gmx.net>;
"r-help at r-project.org" <r-help at r-project.org>
Sent: Friday, July 26, 2013 12:53 AM
Subject: Re: [R] How to split two levels several times?
May be this also helps:
XXX: dataset
rl<-rle(as.character(XXX$electrode))
?dat<-do.call(rbind,lapply(seq_along(rl$lengths),function(i){x1<-if(rl$values[i]=="electrode1"
& (rl$lengths[i]%/%3>1)) rep(3,rl$lengths[i]%/%3) else
rl$lengths[i];data.frame(Len=x1,Val=rl$values[i])}))
?lst1<-split(cumsum(dat[,1]),((seq_along(dat[,1])-1)%/%2)+1)
vec1<-sapply(lst1,max)
vec2<-c(1,vec1[-length(vec1)]+1)
res<-? lapply(seq_along(lst1),function(i) {x1<-lst1[[i]];
XXX[seq(vec2[i],max(x1)),]})
?res
#[[1]]
?#? electrode length
#1 electrode1??? 5.7
#2 electrode1??? 6.3
#3 electrode1??? 6.2
#4 electrode2?? 11.4
#5 electrode2??? 9.7
#
#[[2]]
?# ? electrode length
#6? electrode3?? 14.2
#7? electrode3?? 14.8
#8? electrode3?? 12.6
#9? electrode2?? 11.4
#10 electrode2??? 9.7
#
#[[3]]
?# ? electrode length
#11 electrode4?? 17.0
#12 electrode4?? 16.3
#13 electrode4?? 17.8
#14 electrode4?? 18.3
#15 electrode4?? 16.9
#16 electrode4?? 18.5
#17 electrode1??? 5.7
#18 electrode1??? 6.3
#19 electrode1??? 6.2
#[[4]]
?# ? electrode length
#20 electrode1??? 5.7
#21 electrode1??? 6.3
#22 electrode1??? 6.2
#23 electrode3?? 14.2
#24 electrode3?? 14.8
#25 electrode3?? 12.6
Also, tested in cases like below:
XXX1<- structure(list(electrode = structure(c(1L, 1L, 1L, 2L, 2L, 3L,
3L, 3L, 2L, 2L, 4L, 4L, 4L, 4L, 4L, 4L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 1L, 1L, 1L, 3L, 3L, 3L), .Label = c("electrode1",
"electrode2", "electrode3", "electrode4"), class =
"factor"),
??? length = c(5.7, 6.3, 6.2, 11.4, 9.7, 14.2, 14.8, 12.6, 11.4,
??? 9.7, 17, 16.3, 17.8, 18.3, 16.9, 18.5, 5.7, 6.3, 6.2, 7.7,
??? 7.3, 6.2, 6.7, 6.8, 6.9, 5.7, 6.3, 6.2, 14.2, 14.8, 12.6)), .Names =
c("electrode",
"length"), class = "data.frame", row.names = c(NA, -31L))
XXX2<-structure(list(electrode = structure(c(1L, 1L, 1L, 2L, 2L, 3L,
3L, 3L, 2L, 2L, 4L, 4L, 4L, 4L, 4L, 4L, 1L, 1L, 1L, 1L, 1L, 1L,
1L, 1L, 1L, 3L, 3L, 3L), .Label = c("electrode1",
"electrode2",
"electrode3", "electrode4"), class = "factor"),
length = c(5.7,
6.3, 6.2, 11.4, 9.7, 14.2, 14.8, 12.6, 11.4, 9.7, 17, 16.3, 17.8,
18.3, 16.9, 18.5, 5.7, 6.3, 6.2, 7.7, 7.3, 6.2, 6.7, 6.8, 6.9,
14.2, 14.8, 12.6)), .Names = c("electrode", "length"), class
= "data.frame", row.names = c(NA,
-28L))
rl<-rle(as.character(XXX1$electrode))
?dat<-do.call(rbind,lapply(seq_along(rl$lengths),function(i){x1<-if(rl$values[i]=="electrode1"
& (rl$lengths[i]%/%3>1)) rep(3,rl$lengths[i]%/%3) else
rl$lengths[i];data.frame(Len=x1,Val=rl$values[i])}))
?lst1<-split(cumsum(dat[,1]),((seq_along(dat[,1])-1)%/%2)+1)
vec1<-sapply(lst1,max)
vec2<-c(1,vec1[-length(vec1)]+1)
res1<-? lapply(seq_along(lst1),function(i) {x1<-lst1[[i]];
XXX1[seq(vec2[i],max(x1)),]})
rl<-rle(as.character(XXX2$electrode))
?dat<-do.call(rbind,lapply(seq_along(rl$lengths),function(i){x1<-if(rl$values[i]=="electrode1"
& (rl$lengths[i]%/%3>1)) rep(3,rl$lengths[i]%/%3) else
rl$lengths[i];data.frame(Len=x1,Val=rl$values[i])}))
?lst1<-split(cumsum(dat[,1]),((seq_along(dat[,1])-1)%/%2)+1)
vec1<-sapply(lst1,max)
vec2<-c(1,vec1[-length(vec1)]+1)
res2<-? lapply(seq_along(lst1),function(i) {x1<-lst1[[i]];
XXX2[seq(vec2[i],max(x1)),]})
Didn't test it extensively.? So, it may fail in other situations.
A.K.
----- Original Message -----
From: Rui Barradas <ruipbarradas at sapo.pt>
To: dennis1991 at gmx.net
Cc: r-help at r-project.org
Sent: Thursday, July 25, 2013 2:53 PM
Subject: Re: [R] How to split two levels several times?
Hello,
I think the following does what you want. (I don't know if it makes much
sense but it works.)
lens <- rle(as.character(XXX$electrode))$lengths
m <- length(lens) %/% 2
idx <- rep(1:m, sapply(1:m, function(.m) sum(lens[(2*.m - 1):(2*.m)])))
if(length(lens) %% 2 != 0){
??? idx <- c(idx, rep(m + 1, lens[length(lens)]))
??? sp_idx <- split(idx, idx)
??? n <- length(sp_idx[[m]])
??? if(n %/% 2 < length(sp_idx[[m + 1]]))
??? ??? sp_idx[[m]][(n %/% 2 + 1):n] <- sp_idx[[m + 1]][1]
??? else
??? ??? sp_idx[[m]][(n - length(sp_idx[[m + 1]]) + 1):n] <-? sp_idx[[m +
1]][1]
??? idx <- unlist(sp_idx)
}
sp <- split(XXX, idx)
sp
Rui Barradas
Em 25-07-2013 11:40, dennis1991 at gmx.net escreveu:> Hi Rui
> once more thank you for your help. But the code does so far not solve the
problem because it still treats rows 17-22 (repeated appearance of electrode1)
as one single level. However as can be seen by rows 1-3 (or rows 17-19 and rows
20-22) and the order of the length variable (row 1 = 5.7, row 2 = 6.3, row 3 =
6.2) electrode1 consists only of 3 rows. Maybe that was not made absolutely
clear by me. As described in my mail before if by chance (or systematically) it
happens to be that electrode1 appears right after each other in the table then
the code should split it ?half way?.
>
> So idx should not return
>?? [1] 1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 3 3 3 3 3 3 3 4 4 4
>
> but instead 6 times number 4 at the end
>?? [1] 1 1 1 1 1 2 2 2 2 2 3 3 3 3 3 3 3 3 3 4 4 4 4 4 4
>
> Do you have any solution?
>
>
>> Gesendet: Mittwoch, 24. Juli 2013 um 23:47 Uhr
>> Von: "Rui Barradas" <ruipbarradas at sapo.pt>
>> An: dennis1991 at gmx.net
>> Cc: r-help at r-project.org
>> Betreff: Re: Aw: Re:? Re: [R] How to split two levels several times?
>>
>> Hello,
>>
>> As for the first question, note that in the case you describe, the
>> resulting list of df's will not be a split of the original, there
will
>> be a duplication in the final 4-1 and 1-3. The following is a hack but
>> will do it.
>>
>>
>> lens <- rle(as.character(XXX$electrode))$lengths
>> m <- length(lens) %/% 2
>> idx <- rep(1:m, sapply(1:m, function(.m) sum(lens[(2*.m -
1):(2*.m)])))
>> if(length(lens) %% 2 != 0)
>> ??? idx <- c(idx, rep(m + 1, lens[length(lens)]))
>>
>> sp <- split(XXX, idx)
>>
>> if(length(lens) %% 2 != 0){
>> ??? idx2 <- sp[[m]]$electrode == sp[[m]]$electrode[nrow(sp[[m]])]
>> ??? sp[[m + 1]] <- rbind(sp[[m]][idx2, ], sp[[m + 1]])
>> }
>> sp
>>
>>
>> As for the second question, I'm not understanding it, can you post
>> sample output?
>>
>> Rui Barradas
>>
>> Em 24-07-2013 13:58, dennis1991 at gmx.net escreveu:
>>> Hi Rui
>>> the splitting code worked fine. Thanks for your help. Now I
realized that the code cannot handle a table with levels that by chance (or
systematically) repeatedly appear after each other. For instance this may happen
if I need to extract the final two pairs of the table XXX below:
electrode4+electrode1 and electrode1+electrode3.
>>>
>>> lens <- rle(as.character(XXX$electrode))$lengths
>>> will return 3 2 3 2 6 6 3 and not 3 2 3 2 6 3 3 3 because it counts
electrode1 double.
>>> split(XXX, idx) will produce 3 incorrect outputs instead of the
required 4.
>>> This will also occur if I have systematic combinations 1-4 after
each other for instance in a new table ?XX? below where electrode4 appears
twice.
>>>
>>> Is there a way to make splitting "half-way" between two
of the same levels possible by predefining the length of each individual level?
This would make the splitting code more robust. Thanks for advice.
>>>
>>>
>>> This is the table "XXX"
>>>
>>> electrode length
>>>
>>> electrode1 5.7
>>> electrode1 6.3
>>> electrode1 6.2
>>> electrode2 11.4
>>> electrode2 9.7
>>> electrode3 14.2
>>> electrode3 14.8
>>> electrode3 12.6
>>> electrode2 11.4
>>> electrode2 9.7
>>> electrode4 17.0
>>> electrode4 16.3
>>> electrode4 17.8
>>> electrode4 18.3
>>> electrode4 16.9
>>> electrode4 18.5
>>> electrode1 5.7
>>> electrode1 6.3
>>> electrode1 6.2
>>> electrode1 5.7
>>> electrode1 6.3
>>> electrode1 6.2
>>> electrode3 14.2
>>> electrode3 14.8
>>> electrode3 12.6
>>>
>>>
>>> This is a simplified table XX
>>>
>>> electrode1
>>> electrode2
>>> electrode1
>>> electrode3
>>> electrode1
>>> electrode4
>>> electrode2
>>> electrode1
>>> electrode2
>>> electrode3
>>> electrode2
>>> electrode4
>>> electrode3
>>> electrode1
>>> electrode3
>>> electrode2
>>> electrode3
>>> electrode4
>>> electrode4
>>> electrode1
>>> electrode4
>>> electrode2
>>> electrode4
>>> electrode3
>>>
>>>
>>>
>>>
>>>
>>>
>>>> Gesendet: Dienstag, 23. Juli 2013 um 13:36 Uhr
>>>> Von: "Rui Barradas" <ruipbarradas at sapo.pt>
>>>> An: dennis1991 at gmx.net
>>>> Cc: smartpink111 at yahoo.com, 'r-help' <r-help at
r-project.org>
>>>> Betreff: Re: Aw: Re: [R] How to split two levels several times?
>>>>
>>>> Hello,
>>>>
>>>> It's better if you keep this on the list, the odds of
getting more and
>>>> better answers are greater.
>>>>
>>>> As for your new question, try the following.
>>>>
>>>>
>>>> lens <- rle(as.character(XXX$electrode))$lengths
>>>> m <- length(lens) %/% 2
>>>> idx <- rep(1:m, sapply(1:m, function(.m) sum(lens[(2*.m -
1):(2*.m)])))
>>>> split(XXX, idx)
>>>>
>>>>
>>>> Hope this helps,
>>>>
>>>> Rui Barradas
>>>>
>>>> Em 23-07-2013 11:41, dennis1991 at gmx.net escreveu:
>>>>> Hi
>>>>> this type of splitting works for my specific example.
Thanks for your help.
>>>>>
>>>>> I was not absolutely clear what I generally want. I'm
looking for an option that generally permits splitting two joint levels of a
table after each other. For instance for the table below I want it to be divided
into combinations electrode1-electrode2,? electrode3-electrode2,?
electrode4-electrode1. How should I split this?
>>>>>
>>>>>
>>>>> This is the table "XXX"
>>>>>
>>>>> electrode length
>>>>>
>>>>> electrode1 5.7
>>>>> electrode1 6.3
>>>>> electrode1 6.2
>>>>> electrode2 11.4
>>>>> electrode2 9.7
>>>>> electrode3 14.2
>>>>> electrode3 14.8
>>>>> electrode3 12.6
>>>>> electrode2 11.4
>>>>> electrode2 9.7
>>>>> electrode4 17.0
>>>>> electrode4 16.3
>>>>> electrode4 17.8
>>>>> electrode4 18.3
>>>>> electrode4 16.9
>>>>> electrode4 18.5
>>>>> electrode1 5.7
>>>>> electrode1 6.3
>>>>> electrode1 6.2
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>
>>>>>> Gesendet: Montag, 22. Juli 2013 um 17:53 Uhr
>>>>>> Von: "Rui Barradas" <ruipbarradas at
sapo.pt>
>>>>>> An: dennis1991 at gmx.net
>>>>>> Cc: r-help at r-project.org
>>>>>> Betreff: Re: [R] How to split two levels several times?
>>>>>>
>>>>>> Hello,
>>>>>>
>>>>>> Sorry, I've just realized that your data frame is
named 'XXX', not
>>>>>> 'dat'. Change that and the rest should work:
>>>>>>
>>>>>>
>>>>>> idx <- cumsum(c(TRUE, diff(XXX$electrode ==
"electrode1") > 0))
>>>>>> split(XXX, idx)
>>>>>>
>>>>>>
>>>>>> Rui Barradas
>>>>>>
>>>>>> Em 22-07-2013 16:47, Rui Barradas escreveu:
>>>>>>> Hello,
>>>>>>>
>>>>>>> Try the following.
>>>>>>>
>>>>>>>
>>>>>>> idx <- cumsum(c(TRUE, diff(dat$electrode ==
"electrode1") > 0))
>>>>>>> split(dat, idx)
>>>>>>>
>>>>>>>
>>>>>>> Hope this helps,
>>>>>>>
>>>>>>> Rui Barradas
>>>>>>>
>>>>>>> Em 22-07-2013 15:09, dennis1991 at gmx.net
escreveu:
>>>>>>>> Hi,
>>>>>>>>
>>>>>>>> I have a small problem with the function
split() and would appreciate
>>>>>>>> your help.
>>>>>>>>
>>>>>>>> I have a table called ?XXX? with 2 columns and
49 rows. The 49 rows
>>>>>>>> belong to 8 different levels (electrode1,
...,electrode8). I want to
>>>>>>>> split the table always at the row where
?electrode1? starts again so
>>>>>>>> that I can export 7? individual dataframes
(numbered ?dataframe1? to
>>>>>>>> ?dataframe7?) which contain always electrode1
as first level (always
>>>>>>>> three rows) with the varying number of rows for
electrodes2-8 below.
>>>>>>>> I tried the split function with various setups:
>>>>>>>>
>>>>>>>> t <- as.factor(XXX$electrode)
>>>>>>>>
>>>>>>>> dataframeX <- split(XXX, f=(levels=t))
>>>>>>>>
>>>>>>>> But this doesn?t work. Could you please help.
Thank you! Dennis
>>>>>>>>
>>>>>>>>
>>>>>>>> This is the table "XXX"
>>>>>>>>
>>>>>>>> electrode? ? length
>>>>>>>>
>>>>>>>> electrode1? ? 5.7
>>>>>>>> electrode1? ? 6.3
>>>>>>>> electrode1? ? 6.2
>>>>>>>> electrode2? ? 11.4
>>>>>>>> electrode2? ? 9.7
>>>>>>>> electrode1? ? 5.7
>>>>>>>> electrode1? ? 6.3
>>>>>>>> electrode1? ? 6.2
>>>>>>>> electrode3? ? 14.2
>>>>>>>> electrode3? ? 14.8
>>>>>>>> electrode3? ? 12.6
>>>>>>>> electrode1? ? 5.7
>>>>>>>> electrode1? ? 6.3
>>>>>>>> electrode1? ? 6.2
>>>>>>>> electrode4? ? 17.0
>>>>>>>> electrode4? ? 16.3
>>>>>>>> electrode4? ? 17.8
>>>>>>>> electrode4? ? 18.3
>>>>>>>> electrode4? ? 16.9
>>>>>>>> electrode4? ? 18.5
>>>>>>>> electrode1? ? ....
>>>>>>>> ....? ? ? ? ....
>>>>>>>> electrode5? ? ....
>>>>>>>> ....? ? ? ? ....
>>>>>>>> electrode1? ? ....
>>>>>>>> electrode6? ? ....
>>>>>>>> electrode1? ? ....
>>>>>>>> electrode7? ? ....
>>>>>>>> electrode1? ? ....
>>>>>>>> electrode8? ? ....
>>>>>>>>
>>>>>>>> ______________________________________________
>>>>>>>> R-help at r-project.org mailing list
>>>>>>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>>>>>>> PLEASE do read the posting guide
>>>>>>>> http://www.R-project.org/posting-guide.html
>>>>>>>> and provide commented, minimal, self-contained,
reproducible code.
>>>>>>>>
>>>>>>>
>>>>>>> ______________________________________________
>>>>>>> R-help at r-project.org mailing list
>>>>>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>>>>>> PLEASE do read the posting guide
>>>>>>> http://www.R-project.org/posting-guide.html
>>>>>>> and provide commented, minimal, self-contained,
reproducible code.
>>>>>>
>>>>
>>
______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.