my list al is as below: al=list(c(2,3),5,7)> al[[1]] [1] 2 3 [[2]] [1] 5 [[3]] [1] 7 and I check the second component, its element is 5, then I remove this, now my al is: al[[2]][al[[2]]!=5]->al[[2]]> al[[1]] [1] 2 3 [[2]] numeric(0) [[3]] [1] 7 The Question is, how I can get the new list without the second component, that is :> alwanted[[1]] [1] 2 3 [[2]] [1] 7 Thank you for your help!!! [[alternative HTML version deleted]]
Song -
Set the element to NULL:
> al=list(c(2,3),5,7)
> al[[2]] = NULL
> al
[[1]]
[1] 2 3
[[2]]
[1] 7
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spector at stat.berkeley.edu
On Thu, 24 Jun 2010, song song wrote:
> my list al is as below:
> al=list(c(2,3),5,7)
>> al
> [[1]]
> [1] 2 3
>
> [[2]]
> [1] 5
>
> [[3]]
> [1] 7
>
> and I check the second component, its element is 5, then I remove this,
now
> my al is:
>
> al[[2]][al[[2]]!=5]->al[[2]]
>> al
> [[1]]
> [1] 2 3
>
> [[2]]
> numeric(0)
>
> [[3]]
> [1] 7
>
> The Question is, how I can get the new list without the second component,
> that is :
>
>> alwanted
> [[1]]
> [1] 2 3
>
> [[2]]
> [1] 7
>
> Thank you for your help!!!
>
> [[alternative HTML version deleted]]
>
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>
On Jun 25, 2010, at 1:00 AM, song song wrote:> my list al is as below: > al=list(c(2,3),5,7) >> al > [[1]] > [1] 2 3 > > [[2]] > [1] 5 > > [[3]] > [1] 7 > > and I check the second component, its element is 5, then I remove > this, now > my al is: > > al[[2]][al[[2]]!=5]->al[[2]] >> al > [[1]] > [1] 2 3 > > [[2]] > numeric(0) > > [[3]] > [1] 7 > > The Question is, how I can get the new list without the second > component, > that is : > >> alwanted > [[1]] > [1] 2 3 > > [[2]] > [1] 7Another way: > al=list(c(2,3),5,7) > al[-2] [[1]] [1] 2 3 [[2]] [1] 7 > alwanted <- al[-2] Negative indexing with the "[" operator. -- David.