similar to: ask a question about list in R

my list al is as below: mylist=list(c(2,3),5,7) > mylist [[1]] [1] 2 3 [[2]] [1] 5 [[3]] [1] 7 How could I get the following FOUR lists: First one [[1]] [1] 3 [[2]] [1] 5 [[3]] [1] 7 Second one [[1]] [1] 2 [[2]] [1] 5 [[3]] [1] 7 Third One [[1]] [1] 2 3 [[2]] [1] 7 Last one [[1]] [1] 2 3 [[2]] [1] 5 Do I have to use 'for' loops? Please give me sone suggestions! Thank you

Hi Second question in a day, i'm beginnning to feel incompetent... This time i'm having a weird problem, i'm importing the next data base: >car<-read.csv2("Historicos.csv") 'data.frame': 1818 obs. of 6 variables: $ Dpto : Factor w/ 11 levels "ANTIOQUIA","ATL?NTICO",..: 2 2 2 2 2 1 1 1 1 5 ... $ Rio : Factor w/ 43 levels

Hi, I have a (correlation) matrix and I want to select a subset of its cells depending on the combination of their column and row names. This illustrates my problem: mtrx <- matrix(c(1,2,3,4,5,6,7,8,9), nrow=3, ncol=3, dimnames = list(c('c132','c432', 'c233'), c('r132','r233', 'r432')))> mtrx r132 r233 r432c132 1 4 7c432 2

Hi why I can't do this? m<-c(1,-2,3) m^2.1 with a negative number in it ,but I can do this to a single negative number like -2^2.1~ Thank you ~ JIngsi [[alternative HTML version deleted]]

for example, I have a1=c(1,3,5) a2=c(2,4,6) a3=c(7,8) a4=c(9,10) now if I have i=5, so i in a1, then I get a feedback tag[5]=1 i=8, so i in a3, then can get tag[8]=3 in there any function to do this to check the element belongs to which group? thank you!!! [[alternative HTML version deleted]]

Hi everyone, I am posting this because i know its easy and i cant for the life of me figure out how to do it though i have tried and through a ridiculously complex loop made it happen. I need to convert some list elements of NULL value to 0s so they mesh with my data frame properly. So for A<-list(1,NULL) returns [[1]] [1] 1 [[2]] NULL Would instead return [[1]] [1] 1 [[2]] [1] 0

Hello, All, How can one sort on column and row names. For example: How can this X1 X3 X2 X1 1 0 0 X3 0 1 0 X2 0 0 1 become this? X1 X2 X3 X1 1 0 0 X2 0 1 0 X3 0 0 1 Thank you for your time! Jim [[alternative HTML version deleted]]

Hi R Users, I'm trying to re-order the "site names" ("Waseca", "Morris", ...). I'm using following code: libarry(lattice) barchart(yield ~ variety | site, data = barley, groups = year, layout = c(6,1), aspect=.7, ylab = "Barley Yield (bushels/acre)", scales = list(x = list(abbreviate = TRUE, rot=45,

Hello! I wrote a function that returns a data frame. Nowhere in the function do I say print(my.data.frame), but when I run the function - the data frame is printed on the console. Is there any way to suppress it? Thank you! -- Dimitri Liakhovitski Ninah Consulting www.ninah.com

I am reading in a very large file with names in it and R is truncating the number of rows it reads in. The separator in this file is a pipe '|' and so I use dat <- read.delim('pathToMyFile', header= TRUE, sep='|') It turns out that it is reading up to row 61145 and stopping and I think I see why, but am not sure of the best solution to this problem. I see the name of

May I ask how to initialize a list? usually I will use " result=list(0) " to do this. is this right? [[alternative HTML version deleted]]

Hi everyone I am trying to use grep in a for loop to compare a string value. It works if I use the actual index value but when I use the for loop index, it doesn't work. Any suggestions plz. Here is the code: data <- read.table(file="Sigmoid.csv", head=FALSE, sep=","); c1 <- data$V1 c2 <- data$V2 c3 <- data$V3 c1data <- data.frame(c1); c2data <-

I apologize in advance for the simplicity of this question. I use R 2-3 times a year, and I seem to forget more in the intervening months than I learn during my days of panicked reading.... I HAVE tried looking at the help resources; I'm just not very good at understanding them. I have a dataframe with 18 observations of 5 different things, and a second dataframe with and estimate for those

Hello, I am trying to learn how to perform Multiple Regression Analysis in R. I decided to take a simple example given in this PDF: http://www.utdallas.edu/~herve/abdi-prc-pretty.pdf I created a small CSV called, students.csv that contains the following data: s1 14 4 1 s2 23 4 2 s3 30 7 2 s4 50 7 4 s5 39 10 3 s6 67 10 6 Col headers: Student id, Memory span(Y), age(X1), speech rate(X2) Now

Here's another interesting problem: if you recall I have a data frame (LCvars1) that consists of about 1500 cases (rows) of data from kids who took a test of listening comprehension. The columns are their scores (1 = correct, 0 = incorrect, . = missing) on 140 test items. The items are numbered sequentially and are ordered by increasing difficulty as you go from left to right across the

The structure of the file is clear (see below) the first line is made of integers and doubles with the fifth being a text string followed by arrays of double precision number.: int1 int2 double1 double2 text int3 int4 int5 (array of double) here is an example of file: 1 1 1.0 1.0 "HEAD" 160 224 3 23.4 34.5 ...... I tried to read the first line with readBin (results are copied below):

Hi , SO i have been on a role of asking simple questions lately. So much for feeling like im getting this R business. I wrote a script 2 weeks ago that utilized "proportion" to turn values in a table (from "table") into proportions to then graph. I now get an error that proportion is not a function so im confused. I ran the script a few times and im thinking maybe i had

Dear R Community, I am attempting to transpose a dataset from rows to columns but am stuck. I have tried using reshape() with little luck, possibly due to the categorical nature of the data. For example: id<-c(1,2,2,3,3,3) author<-c("j","k","k","l","l","l")

Hi, I have a matrix and I want to create a matrix that includes every nth column of the original matrix. Does anyone know how I can go about doing that ? Or if you have an idea how I can do the same thing with a data frame ? If you can just point me towards the appropriate function I would appreciate it. Thanks [[alternative HTML version deleted]]

Dear list: I know this may be an old question. I know how to install the packages to a different directory, for example, /home/zrl/tmp and I know how to load it >library("genefilter",lib.loc="/home/zrl/tmp") but I found some package(for example package A) will have to load some other packages as well, and this time package A will look for the package in the original