R help - Dec 2006 - how to transform string to variable name in a fuction?

there is a data frame, like this:
> df
  aa       bb
1  a     20.27802
2  b     22.10664
3  c     21.33470
4  a     22.32898
5  b     19.73760
6  c     20.38979
.....(suppressed)
what I want to do is to copy the data frame's rows into different data
frames according to the levels of 'aa' column, 
> df.a <- df[df[,1]=='a',] ; df.b <- df[df[,1]=='b',] ;
....
> df.a
  aa       bb
1  a 20.27802
4  a 22.32898
...

So, when completed, there should be df.a, df.b,df.c, etc. 
If we could do this by hand, it is pretty fine.  But could I write a loop to do
this ?
when I tried this using a funciton, there is a problem.
> for ( i in levels(df[,1])) {
+  name = paste('df',i,sep='')
+  name <- df[df[,1]==i,]
+ }
> name
  aa       bb
3  c 21.33470
6  c 20.38979
> ls()
[1] "df"   "i"    "name"
> i
[1] "c"
there is not data frames df.a, df.b,etc.

Could you please give me some suggestion?
I have found that write a function in R for a beginner is difficult. Is there 
any tutorial on writing the functions in R?
Furthermore, someone also said that loop is not used as frequently as in other
script language (e.g. bash, perl). So, If you have any other smart means do this
more efficiently, please let me know, I would appreciate your kindness.

	[[alternative HTML version deleted]]

try ?assign

On 12/26/06, jingjiangyan <jingjiangyan at gmail.com>
wrote:
> there is a data frame, like this:
> > df
>   aa       bb
> 1  a     20.27802
> 2  b     22.10664
> 3  c     21.33470
> 4  a     22.32898
> 5  b     19.73760
> 6  c     20.38979
> .....(suppressed)
> what I want to do is to copy the data frame's rows into different data
frames according to the levels of 'aa' column,
> > df.a <- df[df[,1]=='a',] ; df.b <-
df[df[,1]=='b',] ; ....
> > df.a
>   aa       bb
> 1  a 20.27802
> 4  a 22.32898
> ...
>
> So, when completed, there should be df.a, df.b,df.c, etc.
> If we could do this by hand, it is pretty fine.  But could I write a loop
to do this ?
> when I tried this using a funciton, there is a problem.
>
> > for ( i in levels(df[,1])) {
> +  name = paste('df',i,sep='')
> +  name <- df[df[,1]==i,]
> + }
> > name
>   aa       bb
> 3  c 21.33470
> 6  c 20.38979
> > ls()
> [1] "df"   "i"    "name"
> > i
> [1] "c"
> there is not data frames df.a, df.b,etc.
>
> Could you please give me some suggestion?
> I have found that write a function in R for a beginner is difficult. Is
there  any tutorial on writing the functions in R?
> Furthermore, someone also said that loop is not used as frequently as in
other script language (e.g. bash, perl). So, If you have any other smart means
do this more efficiently, please let me know, I would appreciate your kindness.
>
>         [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

-- 
WenSui Liu
A lousy statistician who happens to know a little programming
(http://spaces.msn.com/statcompute/blog)

In the following the components of ss are the data frames in question:

ss <- split(df, df$aa)

On 12/26/06, jingjiangyan <jingjiangyan at gmail.com>
wrote:
> there is a data frame, like this:
> > df
>  aa       bb
> 1  a     20.27802
> 2  b     22.10664
> 3  c     21.33470
> 4  a     22.32898
> 5  b     19.73760
> 6  c     20.38979
> .....(suppressed)
> what I want to do is to copy the data frame's rows into different data
frames according to the levels of 'aa' column,
> > df.a <- df[df[,1]=='a',] ; df.b <-
df[df[,1]=='b',] ; ....
> > df.a
>  aa       bb
> 1  a 20.27802
> 4  a 22.32898
> ...
>
> So, when completed, there should be df.a, df.b,df.c, etc.
> If we could do this by hand, it is pretty fine.  But could I write a loop
to do this ?
> when I tried this using a funciton, there is a problem.
>
> > for ( i in levels(df[,1])) {
> +  name = paste('df',i,sep='')
> +  name <- df[df[,1]==i,]
> + }
> > name
>  aa       bb
> 3  c 21.33470
> 6  c 20.38979
> > ls()
> [1] "df"   "i"    "name"
> > i
> [1] "c"
> there is not data frames df.a, df.b,etc.
>
> Could you please give me some suggestion?
> I have found that write a function in R for a beginner is difficult. Is
there  any tutorial on writing the functions in R?
> Furthermore, someone also said that loop is not used as frequently as in
other script language (e.g. bash, perl). So, If you have any other smart means
do this more efficiently, please let me know, I would appreciate your kindness.
>
>        [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>

I believe the "split" function should work in this case.
 From the help file:

split(x, f, drop = FALSE, ...)
split(x, f, drop = FALSE, ...) <- value
unsplit(value, f, drop = FALSE)


      Arguments

|x| 	vector or data frame containing values to be divided into groups.
|f| 	a ?factor? in the sense that |as.factor <factor.html>(f)| defines 
the grouping, or a list of such factors in which case their interaction 
is used for the grouping.
|drop| 	logical indicating if levels that do not occur should be dropped 
(if |f| is a |factor| or a list).
|value| 	a list of vectors or data frames compatible with a splitting of 
|x|. Recycling applies if the lengths do not match.
|...| 	further potential arguments passed to methods.



Abhijit Dasgupta, Ph.D.

Assistant Professor | Division of Biostatistics
Department of Pharmacology and Experimental Therapeutics | Thomas 
Jefferson University
1015 Chestnut St | Suite M100 | Philadelphia, PA 19107
Ph: (215) 503-9201 | Fax: (215) 503-3804

jingjiangyan wrote:
> there is a data frame, like this:
>   
>> df
>>     
>   aa       bb
> 1  a     20.27802
> 2  b     22.10664
> 3  c     21.33470
> 4  a     22.32898
> 5  b     19.73760
> 6  c     20.38979
> .....(suppressed)
> what I want to do is to copy the data frame's rows into different data
frames according to the levels of 'aa' column,
>   
>> df.a <- df[df[,1]=='a',] ; df.b <-
df[df[,1]=='b',] ; ....
>> df.a
>>     
>   aa       bb
> 1  a 20.27802
> 4  a 22.32898
> ...
>
> So, when completed, there should be df.a, df.b,df.c, etc. 
> If we could do this by hand, it is pretty fine.  But could I write a loop
to do this ?
> when I tried this using a funciton, there is a problem.
>
>   
>> for ( i in levels(df[,1])) {
>>     
> +  name = paste('df',i,sep='')
> +  name <- df[df[,1]==i,]
> + }
>   
>> name
>>     
>   aa       bb
> 3  c 21.33470
> 6  c 20.38979
>   
>> ls()
>>     
> [1] "df"   "i"    "name"
>   
>> i
>>     
> [1] "c"
> there is not data frames df.a, df.b,etc.
>
> Could you please give me some suggestion?
> I have found that write a function in R for a beginner is difficult. Is
there  any tutorial on writing the functions in R?
> Furthermore, someone also said that loop is not used as frequently as in
other script language (e.g. bash, perl). So, If you have any other smart means
do this more efficiently, please let me know, I would appreciate your kindness.
>
> 	[[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>