search for: funciton

Hi! Does anyone know hot to set number of digits to be printed in function 'paste'? Tine Mla?

Hi R folks, How can I generate the discriment function from lda? I have an unbalanced data set. one class has about 25 entries and another class has about 200 entries. I used lda for classification > z<- lda(V3 ~ V1+V2, data) > z Prior probabilities of groups: 0 1 0.91111111 0.08888889 Group means: V1 V2 0 0.4445161 0.04723951 1 0.4058900

Hello everybody, I have encountered a problem with the inverse Gaussian distribution. It is very likely that it will not work regardless of the data input. I have programmed this regression and it works fine no matter which distribution the response comes from. If you run this example (first tried and already got the error) set.seed(1234) y = abs( rnorm(150) ) glm( y ~ ., iris, family =

I've developed a dll (win32) of a bunch of functions prototypes as: /* for building on *nix */ #ifndef WIN32 #define __stdcall /*nothing*/ #endif void __stdcall dbh_2_height( const unsigned long *func_idx, const unsigned long *metric, const unsigned long *species, const double *dbh, double *pred_height ); and have created a R interface

hi, On Sat, Mar 17, 2012 at 2:11 AM, Andrew Trick <atrick at apple.com> wrote: > Yep. I normally do that. I was under some strange impression last night that SmallPtrSetImpl wasn't a template. The patch is incorrect because the SmallPtrSetImpl is neither a template nor has an "insert" function... After a detailed look at the header of SmallPtrSet, I found that the

...ork yfun(10,100,10) # use uniroot to find a solution to the # function in the range -100 to 100 uniroot(yfun(x,10,20),c(-100,100)) My output: > # Define the function > yfun <- function(x,diffMean,diffSE) ((abs(diffMean)-x)/diffSE) > # Prove the function and a call to the funciton works > yfun(10,100,10) [1] 9 > # use uniroot to find a solution to the > # funciton in the range -100 to 100 > uniroot(yfun(x,10,20),c(-100,100)) Error in yfun(x, 10, 20) : object 'x' not found Thank you, John John David Sorkin M.D., Ph.D. Professor of Medicine Chief...

Hi, What is the simplest way to validate a positive integer? validates_numericality_of :foo, :integer_only => true how do I add the positive part? Do I need another validation statement for pattern matching or do I have to write a validate() funciton for my model? Thanks, Peter

Mingxing Tan wrote: > > Hi, all; > > How can I get the number of variables in a function/module (both the > number of variables in original source program and the number of > temporal variables for ssa-form)? > Do you want the SSA values *created* by a function, those used by a function, or both? For SSA values, simply iterate over all of the instructions within the

Hi, all; How can I get the number of variables in a function/module (both the number of variables in original source program and the number of temporal variables for ssa-form)? I’m dealing with some dataflow analysis problem and need the information of variables. Appreciate any help. Thanks. Star.Tan -------------- next part -------------- An HTML attachment was scrubbed... URL:

Hello I am wondering, how do I find if R has a certain funciton to do a given task. do I just type help.search("rate"). I am just trying to find a function to calculate the rate of change for a variable. I could come up with one if there isn't any allready builtin. thanks

Windows XP R 2.3.1 I have a funciton fit1<-lm(y~x+z) Is there a function that will produce a 3-dimensional plot of y,x,z? I looked at the help files, but did not find a clean answer to my question. Thanks, John John Sorkin M.D., Ph.D. Chief, Biostatistics and Informatics University of Maryland School of Medicine Division of Gero...

...uments in my own function. For example, I have a function that looks like this: my.f <- function(a = x1, b = x2) { x1 = equation 1 x2 = equation 2 x3 = equation 3 y = a + b } x1, x2, and x3 are temporary variables (intermediate results) calculated from other variables within the funciton. I want to use two of these three variables to calculate y, and write R script as below: my.f(a = x1, b = x2) or my.f(a = x2, b = x3) The error information shows that: ?objects 'x1', 'x2', or 'x3' not found?. Can anybody help me solve this problem? Thanks in advance....

...ind a solution to the > # function in the range -100 to 100 > uniroot(yfun(x,10,20),c(-100,100)) > > > My output: >> # Define the function >> yfun <- function(x,diffMean,diffSE) ((abs(diffMean)-x)/diffSE) >> # Prove the function and a call to the funciton works >> yfun(10,100,10) > [1] 9 >> # use uniroot to find a solution to the >> # funciton in the range -100 to 100 >> uniroot(yfun(x,10,20),c(-100,100)) > Error in yfun(x, 10, 20) : object 'x' not found The problem is that uniroot() wants a functio...

Hi, I would like to conduct a MANOVA. I know that there 's the manova() funciton and the summary.manova() function to get the appropriate summary of test statistics. I just don't manage to specify my model in the manova() call. How to specify a model with multiple responses and one explanatory factor? If I type: pcor.manova<-manova(isol+hcom+habarea+inclin+windprot+shr...

...n my h extension. exp.. exten => h,n,Set(CDR(cause_code)=${HANGUPCAUSE}) I need the cause code stored. Really what I need to be able to do is in the h quickly store some values to the CDR then. For the write of the CDR and stopping the billing seconds. Then continue to process some cleanup funcitons. How can I work arround asterisk not honoring the endbeforehexten=no. Is there some other way to achieve this? Bryant I need the cause code stored.Really what I need to be able to do is in the h quickly store some values to the CDR then.For the write of the CDR and stopping the billing seconds...

I am writing my thesis with the function gam(), with the package {mgcv}. My command is: gam(y~s(x1,bs="cr")+s(x2, bs="cr")). I need help to know what are the default basis funcitons for gam. I have not found any detailed reference for this. Can anyone help me with this?? -- View this message in context: http://www.nabble.com/help%3A-what-are-the-basis-functions-in-%7Bmgcv%7D%3A-gam--tp22673295p22673295.html Sent from the R help mailing list archive at Nabble.com.

...2007 and have installed the asterisk svn 1.4 with success. I also used the patch for cellphones and it works perfectly. I was that happy that I decided to buy a TDM11B and it works. Now, I want to study a bit the code used by this people. Does anybody know how can I go deeper in this code with funcitonal bloqs in order to understand how is possible to interface that much new technologies? I know there is a book available but I am not in a mood for buying it. Any ideas? Thanks in Advance, Iban _________________________________________________________________ Un amor, una aventura, compa??a p...

Hi guys, I have a server in Debian 8 with Samba 4.2.2 compiled about sources. This server is my project for small busines and run all network funcitons. The functions like AD, DNS, DHCP, NTP, File Server, Print Server, Openfire, OCS, GLPI, Squid and Squidguard are work integrated on Domain perfectly. My problem is that some clients need run a windows aplication so I put a windows server as member server but I canot access Windows Server via RDP c...

Op 04/01/2019 om 11:17 schreef Joan Moreau via dovecot: > > Why not, but please guide me about the core structure (mandatory > funcitons, etc..) of a typical Dovecot FTS plugin > The Dovecot API documentation is not exhaustive everywhere, but the basics are documented. The remaining questions can be answered by looking at examples found in similar plugins or the relevant API sources. I know of one FTS plugin not written by Do...

...df[df[,1]=='a',] ; df.b <- df[df[,1]=='b',] ; .... > df.a aa bb 1 a 20.27802 4 a 22.32898 ... So, when completed, there should be df.a, df.b,df.c, etc. If we could do this by hand, it is pretty fine. But could I write a loop to do this ? when I tried this using a funciton, there is a problem. > for ( i in levels(df[,1])) { + name = paste('df',i,sep='') + name <- df[df[,1]==i,] + } > name aa bb 3 c 21.33470 6 c 20.38979 > ls() [1] "df" "i" "name" > i [1] "c" there is not data fra...