Here is a function I use:
my.ls <- function(pos=1, sorted=F){
.result <- sapply(ls(pos=pos, all.names=TRUE),
function(..x)object.size(eval(as.symbol(..x))))
if (sorted){
.result <- rev(sort(.result))
}
.ls <-
as.data.frame(rbind(as.matrix(.result),"**Total"=sum(.result)))
names(.ls) <- "Size"
.ls$Size <- formatC(.ls$Size, big.mark=',', digits=0,
format='f')
.ls$Mode <- c(unlist(lapply(rownames(.ls)[-nrow(.ls)],
function(x)mode(eval(as.symbol(x))))), '-------')
.ls
}
On 9/27/06, Ben Fairbank <BEN at ssanet.com>
wrote:> Does R provide a function analogous to LS() or str() that reports the
> storage space, on disk or in memory, required by objects?
>
> Ben Fairbank
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
--
Jim Holtman
Cincinnati, OH
+1 513 646 9390
What is the problem you are trying to solve?