You'd have to use 2 queues. After 5 minutes, exit queue 1, enter queue 2
that has a different periodic announcement. Since everybody leaves queue 1
after 5 minutes, they will enter queue 2 in the same order as they left queue 1.
Mike
-----Original Message-----
From: asterisk-users-bounces at lists.digium.com [mailto:asterisk-users-bounces
at lists.digium.com] On Behalf Of Carlos Chavez
Sent: Wednesday, January 12, 2011 2:15 PM
To: Asterisk
Subject: [asterisk-users] Queue periodic announce...
Is there a way to play a different message than the periodic announce after a
certain time? I have been asked by a customer to do something like this:
The user enters the queue.
We play position and periodic announce every 60 seconds.
If user has waited for more than 5 minutes then play a message with option to
leave a voicemail
This means that I would have to be able to play a different message after five
minutes. I thought I could solve this by having the user leave the queue after
5 minutes, play the message with the option for voicemail and then reinserting
them into the queue but I cannot find a way to put the user back in the same
position they were when the timeout occurred. Any ideas on how to implement
this? We are using Asterisk
1.6.2.15 with Queuemetrics.
--
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Carlos Ch vez Prats
Director de Tecnolog a
+52-55-91169161 ext 2001