R help - Jun 2008 - mapping one redundant index to another redundant index

Dear R users,

I have a simple problem I cannot solve, but I sure you can help.

I have two vector, let say
> tmp1 <- c("a", "a", "b", "c")
> tmp2 <- c("a", "a", "b", "c",
"c", "d")
and I want to create a matrix of two column for which I have all the
combinations of the same character, let say like this
> tmp3
     tmp1 tmp2
[1,] "a"  "a"
[2,] "a"  "a"
[3,] "a"  "a"
[4,] "a"  "a"
[5,] "b"  "b"
[6,] "c"  "c"
[7,] "c"  "c"


how can I perform this task?


thank you!

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merge(tmp1, tmp2) gives the basic data and you can put it
in the form requested using:

Tmp1 <- data.frame(x = tmp1)
Tmp2 <- data.frame(x = tmp2)

M <- merge(Tmp1, Tmp2)
data.frame(tmp1 = M$x, tmp2 = M$x)

or using Tmp1 and Tmp2 from above:

library(sqldf)
sqldf("select x tmp1, x tmp2 from Tmp1 natural join Tmp2")

See sqldf home page at:
http://sqldf.googlecode.com


On Sat, Jun 28, 2008 at 7:38 AM, John Lande <john.lande77 at gmail.com>
wrote:
> Dear R users,
>
> I have a simple problem I cannot solve, but I sure you can help.
>
> I have two vector, let say
>
>> tmp1 <- c("a", "a", "b",
"c")
>> tmp2 <- c("a", "a", "b",
"c", "c", "d")
>
> and I want to create a matrix of two column for which I have all the
> combinations of the same character, let say like this
>
>> tmp3
>     tmp1 tmp2
> [1,] "a"  "a"
> [2,] "a"  "a"
> [3,] "a"  "a"
> [4,] "a"  "a"
> [5,] "b"  "b"
> [6,] "c"  "c"
> [7,] "c"  "c"
>
>
> how can I perform this task?
>
>
> thank you!
>
>        [[alternative HTML version deleted]]
>
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