?findInterval() could be of help in this case.
Best,
Dimitris
----
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
http://www.student.kuleuven.be/~m0390867/dimitris.htm
Quoting halldor bjornsson <halldor.bjornsson at gmail.com>:
> I have corrected a typo in my previous posting. In what follows the
> line with the inequality is correct
>
> Hi ,
>
> I have two sorted vectors X and Xi, where the range of Xi lies within the
> range of X.
>
> For an element in Xi, I want to find the neigbouring data in X, e.g. find
an
> index ix
> so that for element number k, then
> X[ix[k]] < Xi[k] < X[ix[k] +1] # also OK with "<=" on
either one, but not
> both
>
> This is easy to code by looping over the data in X,Xi, but I suspect there
> may be a faster and more elegant way to do this in R.
>
> In Python (Numeric) the same can be achieved with
> ix=Numeric.searchsorted(X[1:-1],Xi),
> which is quite compact.
>
> So, does anyone know of a corresponding R call that can achive the same?
>
> Sincerely,
> Halld?r
>
>
> --
> Halld?r Bj?rnsson
> Deildarstj. Ranns. & ?r?un
> Ve?ursvi? Ve?urstofu ?slands
>
> Halld?r Bjornsson
> Weatherservice R & D
> Icelandic Met. Office
>
> [[alternative HTML version deleted]]
>
>
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