Hi Rangesh,
Perhaps I mis-understand your question, but it could be as simple as...
p <- 1-exp(-exp(s))
In R, this is vectorized such that a new vector is calculated - one
value for each value of s, so p will have the same length as s.
In the "Introduction to R" read up on vectors and how to avoid loops.
cheers!
Sean
On 06/08/05, Rangesh Kunnavakkam <rangeshk at gmail.com>
wrote:> I am new to R,so excuse me if its too basic. I have a vector of scores
> S= {s1,s2,s3,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,sn}
> n could be very large.
> I want to find p-value for each score and I have the formula
> pvalue= 1-exp(-exp(S))
> so any ideas how to get this new vector P={p1,p2,p3,p4,p5....pn}
> thankyou in advance
> Rangesh
>
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