R help - Jan 2012 - choosing items from array: very stupid and simple question

x<-1:11
y<-2:3

is there a way to do something like
x[x==y]
(which actually produce error)?
I am really got stuck

> x[x %in%  y]
[1] 2 3
>

2012/1/8 Philipp Chapkovski <chapkovski at
gmail.com>:
> x<-1:11
> y<-2:3
>
> is there a way to do something like
> x[x==y]
> (which actually produce error)?
> I am really got stuck
>
-- 
Sarah Goslee
http://www.functionaldiversity.org

This does literally what you asked for
> x[x %in% y]
[1] 2 3

This is more likely what you want
> which(x %in% y)
[1] 2 3
>
It is an artifact of this example that the two results look the same.  Here
is a different example
that distinguishes them, and in this example, %in% is probably not right
either.  match() would be better.
> x <- sample(100, 11)
> x
 [1] 99 76 97 65 20 70 32  6 80 16 51
> y <- c(65, 99)
> y
[1] 65 99
> x %in% y
 [1]  TRUE FALSE FALSE  TRUE FALSE FALSE FALSE FALSE FALSE FALSE
FALSE
> x[x %in% y]
[1] 99 65
> which(x %in% y)
[1] 1 4
> mm <- match(y, x, 0)
> mm
[1] 4 1
> x[mm]
[1] 65 99
>
We care because this is only useful if there is more than one column.
> xx <- cbind(x, 11:21)
> xx[mm,]
      x
[1,] 65 14
[2,] 99 11
>
> ## compare to
> xx[which(x %in% y),] ## same rows but in wrong order
      x
[1,] 99 11
[2,] 65 14
>
Rich


2012/1/8 Philipp Chapkovski <chapkovski@gmail.com>
> x<-1:11
> y<-2:3
>
> is there a way to do something like
> x[x==y]
> (which actually produce error)?
> I am really got stuck
>
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