Rails - Mar 2010 - file upload error(can't convert Tempfile into String)

i tried a method   to implementa file uploader  by  using amethod  below

this is ma  controlller   method   to upload

def save_imports
    Contactslist.save(params[:list])
    render :text => "File uploaded successfully"


this is ma view  file


.remote
  - form_for(@list, :url=> save_imports_list_path(@list, :format =>
"js"), :html => { :multipart => true, :target =>
"uploading", :onsubmit
=> "$(''list_submit).disabled = true" }) do |f|
    = link_to_close edit_list_path(@list)
    .section
      %small
        #{t :add_contacts_from_file}
      %table{ :width => 500, :cellpadding => 0, :cellspacing => 0 }
        %tr
          %td{ :valign => :top }
          .label.top.req #{t :upload_new}:
          =f.file_field  :uploads, :style => "width:240px"

    .buttonbar
      = f.submit "#{t:save_contacts}", :onclick =>
"this.disabled true"
      #{t :or}
      = link_to_cancel edit_list_path(@list)

i created   amodel  contact list and   nclude  amethod  as given  below


class Contactslist < ActiveRecord::Base
def self.save(upload)
    name =  upload[''uploads'']
    puts name
    directory = "public/avatars"
    # create the file path
    path = File.join(directory, name)
    # write the file
    File.open(path, "wb") { |f|
f.write(upload[''uploads''].read) }
  end
end
when i tried   to upload a file its  showing  errors  as



 TypeError in ListsController#save_imports

can''t convert Tempfile into String


can  anyone  help.is there any  fault in this  method?actually i  wanted
toupload this  files into a table callled contactslists or  to move  to
a  folder in  my application  pls  provide  help
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Hey Tony,

You just need

  name =  upload[''uploads''].original_filename

instead of

  name =  upload[''uploads'']

/Lasse

2010/3/26 Tony Augustine <lists-fsXkhYbjdPsEEoCn2XhGlw@public.gmane.org>
> i tried a method   to implementa file uploader  by  using amethod  below
>
> this is ma  controlller   method   to upload
>
> def save_imports
>    Contactslist.save(params[:list])
>    render :text => "File uploaded successfully"
>
>
> this is ma view  file
>
>
> .remote
>  - form_for(@list, :url=> save_imports_list_path(@list, :format =>
> "js"), :html => { :multipart => true, :target =>
"uploading", :onsubmit
> => "$(''list_submit).disabled = true" }) do |f|
>    = link_to_close edit_list_path(@list)
>    .section
>      %small
>        #{t :add_contacts_from_file}
>      %table{ :width => 500, :cellpadding => 0, :cellspacing => 0 }
>        %tr
>          %td{ :valign => :top }
>          .label.top.req #{t :upload_new}:
>          =f.file_field  :uploads, :style => "width:240px"
>
>    .buttonbar
>      = f.submit "#{t:save_contacts}", :onclick =>
"this.disabled > true"
>      #{t :or}
>      = link_to_cancel edit_list_path(@list)
>
> i created   amodel  contact list and   nclude  amethod  as given  below
>
>
> class Contactslist < ActiveRecord::Base
> def self.save(upload)
>    name =  upload[''uploads'']
>    puts name
>    directory = "public/avatars"
>    # create the file path
>    path = File.join(directory, name)
>    # write the file
>    File.open(path, "wb") { |f|
f.write(upload[''uploads''].read) }
>  end
> end
> when i tried   to upload a file its  showing  errors  as
>
>
>
>  TypeError in ListsController#save_imports
>
> can''t convert Tempfile into String
>
>
> can  anyone  help.is there any  fault in this  method?actually i  wanted
> toupload this  files into a table callled contactslists or  to move  to
> a  folder in  my application  pls  provide  help
> --
> Posted via http://www.ruby-forum.com/.
>
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> .
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Lasse Bunk wrote:
> Hey Tony,
> 
> You just need
> 
>   name =  upload[''uploads''].original_filename
> 
> instead of
> 
>   name =  upload[''uploads'']
> 
> /Lasse
> 
> 2010/3/26 Tony Augustine
<lists-fsXkhYbjdPsEEoCn2XhGlw@public.gmane.org>
thanks a  lot its  working  now
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