R help - Jul 2014 - using match to obtain non-sorted index values from non-sorted vector

Hello all,

I've been struggling with the best way to find index values from a large
vector with elements that will match elements of a subset vector [the
table argument in match()]. 

BUT the index values can't come out sorted (as we'd get in  which(X %in%
Y) ).

My 'population' vector can't be sorted. 

pop.df <- data.frame(pop=c(1,6,4,3,10)) 

The subset:  Tset = c(10,3,6)

 

So I'd like to get these index values (from pop.df) , in this order:
5,4,2

 

If it could be sorted I could use:

which(sort(pop.df$pop) %in% sort(Tset))

 

But sorting will cause more grief later, so best not mess with it.

Here is my hopefully adequate MWE of a solution. I'm keen to see if
anybody has a better suggestion. 

Thanks!

_____________________

###BEGIN R

#pop is the full set of values, it has no info on their ranking

# I don't want to sort these data. They need to remain in this order.

pop.df <- data.frame(pop=c(1,6,4,3,10))

 

#rank.df is my dataframe that tells me the top three rankings (derived
elsewhere)

rank.df <- data.frame(rank=1:3, Tset = c(10,3,6))   # Target set

 

#match.df will be my source of row index based on rank

match.df <- data.frame(match.vec= match(pop.df$pop, table=rank.df$Tset),
index.vec=1:nrow(pop.df))

 

#rank.df will now include the index location in the pop.df where I can
find the top three ranks.

rank.df  <- merge(rank.df, match.df, by.x='rank',
by.y='match.vec')

rank.df

 

####END

 

_______________________________________________________

Michael Folkes

Salmon Stock Assessment

Canadian Dept. of Fisheries & Oceans     

Pacific Biological Station

3190 Hammond Bay Rd.

Nanaimo, B.C., Canada

V9T-6N7

Ph (250) 756-7264 Fax (250) 756-7053  Michael.Folkes@dfo-mpo.gc.ca
<mailto:Michael.Folkes@dfo-mpo.gc.ca> 




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