Dear R People:
I'm sure that this is a very simple problem, but I have been wresting with
it for some time.
I have the following file that has the following one line:
CRS("+init=epsg:28992")
Fair enough. I scan it into R and get the following:
> u
[1] "CRS(\"+init=epsg:28992\")"> gsub(pattern='\"',replacement='"',x=u)
[1] "CRS(\"+init=epsg:28992\")"
I need to get rid of the extra quotation marks and slashes. I've tried all
sorts of things, including gsub, as you see, but no good.
Thank you for any help.
Sincerely,
Erin
--
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodgess@gmail.com
[[alternative HTML version deleted]]
(1) The backslashes are not really there; they are an artefact of the R
print() function.
Try cat(u,"\n"). I think this might be an FAQ.
(2) Is not your problem the fact that your are setting "replacement"
equal to the
thing you are trying to get rid of? I.e. don't you want
v <- gsub(pattern='\"',replacement='',x=u) ???
Either I am misunderstanding your intent or you need another cup of coffee.
cheers,
Rolf
On 11/18/13 11:07, Erin Hodgess wrote:> Dear R People:
>
> I'm sure that this is a very simple problem, but I have been wresting
with
> it for some time.
>
> I have the following file that has the following one line:
>
> CRS("+init=epsg:28992")
>
> Fair enough. I scan it into R and get the following:
>
>> u
> [1] "CRS(\"+init=epsg:28992\")"
>> gsub(pattern='\"',replacement='"',x=u)
> [1] "CRS(\"+init=epsg:28992\")"
>
> I need to get rid of the extra quotation marks and slashes. I've tried
all
> sorts of things, including gsub, as you see, but no good.
R. Michael Weylandt <michael.weylandt@gmail.com>
2013-Nov-17 22:42 UTC
[R] quotation marks and scan
They're not actually there so don't try too hard to rid yourself of them: x <- "\'" length(x) print(x) cat(x, "\n") Make sure you're clear on the difference between what's stored by the computer and what it print()s. Rarely the same, though cat() is often slightly more honest. On Nov 17, 2013, at 17:07, Erin Hodgess <erinm.hodgess at gmail.com> wrote:> Dear R People: > > I'm sure that this is a very simple problem, but I have been wresting with > it for some time. > > I have the following file that has the following one line: > > CRS("+init=epsg:28992") > > Fair enough. I scan it into R and get the following: > >> u > [1] "CRS(\"+init=epsg:28992\")" >> gsub(pattern='\"',replacement='"',x=u) > [1] "CRS(\"+init=epsg:28992\")" > > I need to get rid of the extra quotation marks and slashes. I've tried all > sorts of things, including gsub, as you see, but no good. > > Thank you for any help. > > Sincerely, > Erin > > > -- > Erin Hodgess > Associate Professor > Department of Computer and Mathematical Sciences > University of Houston - Downtown > mailto: erinm.hodgess at gmail.com > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.
On Sun, Nov 17, 2013 at 10:42 PM, R. Michael Weylandt <michael.weylandt at gmail.com> <michael.weylandt at gmail.com> wrote:> They're not actually there so don't try too hard to rid yourself of them: > > x <- "\'" > > length(x) > print(x) > cat(x, "\n")Did you mean to do 'nchar(x)' to show that \" was one character? 'length' gives the number of elements in a vector, which in this case is also one. > x=c("\"", '\'') > length(x) [1] 2 > nchar(x) [1] 1 1
I know you have a solution, but I would have suggested using print() with quote=FALSE as a better way to illuminate what is going on, as in this example:> foo <- 'bah"bah' > foo[1] "bah\"bah"> print(foo)[1] "bah\"bah"> print(foo, quote=FALSE)[1] bah"bah As others said, the backslash isn't really there. So you only have to get rid of the " which you can do with> gsub('"','',foo)[1] "bahbah" To summarize, in R, due to its rules for formatting printed output, what you see isn't always exactly what you have, and this is an example. -- Don MacQueen Lawrence Livermore National Laboratory 7000 East Ave., L-627 Livermore, CA 94550 925-423-1062 On 11/17/13 2:07 PM, "Erin Hodgess" <erinm.hodgess at gmail.com> wrote:>Dear R People: > >I'm sure that this is a very simple problem, but I have been wresting with >it for some time. > >I have the following file that has the following one line: > > CRS("+init=epsg:28992") > >Fair enough. I scan it into R and get the following: > >> u >[1] "CRS(\"+init=epsg:28992\")" >> gsub(pattern='\"',replacement='"',x=u) >[1] "CRS(\"+init=epsg:28992\")" > >I need to get rid of the extra quotation marks and slashes. I've tried >all >sorts of things, including gsub, as you see, but no good. > >Thank you for any help. > >Sincerely, >Erin > > >-- >Erin Hodgess >Associate Professor >Department of Computer and Mathematical Sciences >University of Houston - Downtown >mailto: erinm.hodgess at gmail.com > > [[alternative HTML version deleted]] > >______________________________________________ >R-help at r-project.org mailing list >https://stat.ethz.ch/mailman/listinfo/r-help >PLEASE do read the posting guide >http://www.R-project.org/posting-guide.html >and provide commented, minimal, self-contained, reproducible code.