I have a variable that is course #
nCourse <-
as.factor(c("002A","002B","002C","007A","007B","007C","101","118A","118B","118C"))
And I would like to get rid of the leading zeros, and have the following
set
("2A","2B","2C","7A","7B","7C","101","118A","118B","118C")
to paste()
together with the department, "B","P","C" (bio,
phys, & chem etc)
I am stuck trying to figure out regular expressions, they are new to me.
Thank You very much
[[alternative HTML version deleted]]
Hello,
Try the following.
gsub("^0+", "", as.character(nCourse))
Hope this helps,
Rui Barradas
Em 01-09-2013 21:41, Robert Lynch escreveu:> I have a variable that is course #
> nCourse <-
>
as.factor(c("002A","002B","002C","007A","007B","007C","101","118A","118B","118C"))
>
> And I would like to get rid of the leading zeros, and have the following
> set
>
("2A","2B","2C","7A","7B","7C","101","118A","118B","118C")
to paste()
> together with the department, "B","P","C"
(bio, phys, & chem etc)
>
> I am stuck trying to figure out regular expressions, they are new to me.
>
> Thank You very much
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
Hi,
?levels(nCourse)<-gsub("^0+","",levels(nCourse))
?nCourse
# [1] 2A?? 2B?? 2C?? 7A?? 7B?? 7C?? 101? 118A 118B 118C
#Levels: 2A 2B 2C 7A 7B 7C 101 118A 118B 118C
#The second part is not very clear.
res<-setNames(data.frame(lapply(c("B","P","C"),function(x)
paste0(levels(nCourse),x)),stringsAsFactors=FALSE),c("B","P","C"))
head(res)
#??? B?? P?? C
#1 2AB 2AP 2AC
#2 2BB 2BP 2BC
#3 2CB 2CP 2CC
#4 7AB 7AP 7AC
#5 7BB 7BP 7BC
#6 7CB 7CP 7CC
A.K.
----- Original Message -----
From: Robert Lynch <robert.b.lynch at gmail.com>
To: R help <r-help at r-project.org>
Cc:
Sent: Sunday, September 1, 2013 4:41 PM
Subject: [R] string processing(regular expressions)
I have a variable that is course #
nCourse <-
as.factor(c("002A","002B","002C","007A","007B","007C","101","118A","118B","118C"))
And I would like to get rid of the leading zeros, and have the following
set
("2A","2B","2C","7A","7B","7C","101","118A","118B","118C")
to paste()
together with the department, "B","P","C" (bio,
phys, & chem etc)
I am stuck trying to figure out regular expressions, they are new to me.
Thank You very much
??? [[alternative HTML version deleted]]
______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.