Displaying 1 result from an estimated 1 matches for "ncourse".
Did you mean:
course
2013 Sep 01
2
string processing(regular expressions)
I have a variable that is course #
nCourse <-
as.factor(c("002A","002B","002C","007A","007B","007C","101","118A","118B","118C"))
And I would like to get rid of the leading zeros, and have the following
set
("2A","2B",&...