> sapply(seq(4,ncol(dat)), function(i)
survdiff(Surv(time,completion=="2")~dat[,i], data=dat,
subset=group=="3")$chisq)
[1] 0.0944 4.4854 3.4990
Chris
-----Original Message-----
From: Charles Determan Jr [mailto:deter088 at umn.edu]
Sent: Thursday, October 18, 2012 3:04 PM
To: r-help at r-project.org
Subject: [R] looping survdiff?
Hello,
I am trying to set up a loop that can run the survdiff function with the
ultimate goal to generate a csv file with the p-values reported. However,
whenever I try a loop I get an error such as "invalid type (list) for
variable 'survival_data_variables[i]".
This is a subset of my data:
structure(list(time = c(1.51666666666667, 72, 72, 25.7833333333333, 72, 72, 72,
72, 72, 72, 1.18333333333333, 0.883333333333333, 1.15, 0.866666666666667, 72,
1.03333333333333, 72, 1.05, 72, 22.7666666666667), group = c(2L, 1L, 3L, 3L, 3L,
4L, 4L, 1L, 3L, 3L, 3L, 3L, 4L, 3L, 3L, 4L, 3L, 4L, 3L, 4L), completion =
structure(c(2L, 1L, 1L, 2L, 1L, 1L, 1L, 1L, 1L, 1L, 2L, 2L, 2L, 2L, 1L, 2L, 1L,
2L, 1L, 2L), .Label = c("1", "2"), class =
"factor"), var1 = structure(c(2L, 2L, 3L, 1L, 1L, 3L, 1L, 1L, 1L, 3L,
2L, 2L, 4L, 3L, 2L, 4L, 2L, 4L, 2L, 4L), .Label = c("1",
"2", "3", "4"), class = "factor"),
var2 = structure(c(3L, 3L, 1L, 1L, 2L, 4L, 3L,
3L, 2L, 4L, 2L, 1L, 2L, 1L, 2L, 2L, 4L, 4L, 2L, 3L), .Label =
c("1",
"2", "3", "4"), class = "factor"),
var3 = structure(c(4L,
2L, 3L, 1L, 3L, 4L, 4L, 2L, 2L, 4L, 2L, 2L, 1L, 2L, 2L, 2L,
1L, 3L, 4L, 1L), .Label = c("1", "2", "3",
"4"), class = "factor")), .Names = c("time",
"group", "completion", "var1", "var2",
"var3"), row.names = c(NA, 20L), class = "data.frame")
The loop I have been trying for just group 3 is:
d=data.frame()
for(i in 4:6){
a=assign(paste("p-value",i,sep=""),
survdiff(Surv(time, completion=="2")~dat[i],
data=dat[group=="3",],
rho=0))
b=as.matrix(a$chisq)
d=rbind(d, b)
write.csv(d, file="C:/.../junk.csv", quote=FALSE)}
Perhaps I am making this more difficult than it needs to be. Thanks for any
help,
Charles
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