Displaying 3 results from an estimated 3 matches for "survival_data_variables".
2012 Oct 17
2
loop of quartile groups
...1=factor(brks, labels=1:4)
However, I cannot get a loop to work nor can I get a loop to add the
columns with an appropriate name (ex. quartile_variable). I have tried
multiple different ways but can't seem to get it to work. I think it would
begin something like this:
for(i in 11:ncol(survival_data_variables)){
brks=as.data.frame(with(survival_data_variables,
cut2(survival_data_variables[,i], g=4)))
Any assistance would be sincerely appreciated. I would like the final data
set to have the following layout:
ID var1 var2 var3 var4 quartile var1
quart...
2012 Oct 18
1
looping survdiff?
Hello,
I am trying to set up a loop that can run the survdiff function with the
ultimate goal to generate a csv file with the p-values reported. However,
whenever I try a loop I get an error such as "invalid type (list) for
variable 'survival_data_variables[i]".
This is a subset of my data:
structure(list(time = c(1.51666666666667, 72, 72, 25.7833333333333,
72, 72, 72, 72, 72, 72, 1.18333333333333, 0.883333333333333,
1.15, 0.866666666666667, 72, 1.03333333333333, 72, 1.05, 72,
22.7666666666667), group = c(2L, 1L, 3L, 3L, 3L, 4L, 4L,
1L, 3L, 3L,...
2012 Oct 19
1
Looping survdiff
...t at r-project.org wrote:
> Hello,
>
> I am trying to set up a loop that can run the survdiff function with the
> ultimate goal to generate a csv file with the p-values reported. However,
> whenever I try a loop I get an error such as "invalid type (list) for
> variable 'survival_data_variables[i]".
>
> This is a subset of my data:
>
> structure(list(time = c(1.51666666666667, 72, 72, 25.7833333333333,
> 72, 72, 72, 72, 72, 72, 1.18333333333333, 0.883333333333333,
> 1.15, 0.866666666666667, 72, 1.03333333333333, 72, 1.05, 72,
> 22.7666666666667), group = c(2L, 1L...