Dear all, in one part of my code I want to sum two vectors element-wise the problem is that either the 1st vector or the 2nd vector always have one or two less elements example of my problem In TotalVector + (datalist2[[1]]$dataset$Results[[j]]$Results[[time]]$Sweep) : Länge des längeren Objektes ist kein Vielfaches der Länge des kürzeren Objektes Browse[1]> str(TotalVector) int [1:10308] 3032 3048 3075 2978 3026 3012 2933 2987 3063 3038 ... Browse[1]> str(datalist2[[1]]$dataset$Results[[j]]$Results[[time]]$Sweep) int [1:10307] 2 1 3 1 5 6 3 1 0 2 ... as you can see the two vectors differ only in one element. As the sample is quite large it would be the same if I ignore the one extra element. There are times though that the missing elements can be 2 or 3 (but always the number is small enough so to be ignored) The major concern is that this "difference" can be either on the fist vector or either on the second vector. If I try to solve that with simple if statements the code gets too much of spaghetti... Is there a simple way when there is this length difference either to a. Ignore the extra elements -or- b. Add the elements missing to the vector with the smaller length( one can just duplicate some of the existing values to reach the needed length) How I can do either a or b? I would like to thank you in advance for your help Regards Alex [[alternative HTML version deleted]]
Hi, Please check this link: (http://r.789695.n4.nabble.com/calculations-with-vectors-of-unequal-length-td3477848.html) A.K. ----- Original Message ----- From: Alaios <alaios at yahoo.com> To: R help <R-help at r-project.org> Cc: Sent: Friday, August 3, 2012 9:13 AM Subject: [R] Sum two Vectors of different length Dear all, in one part of my code I want to sum two vectors element-wise the problem is that either the 1st vector or the 2nd vector always have one or two less elements example of my problem In TotalVector + (datalist2[[1]]$dataset$Results[[j]]$Results[[time]]$Sweep) : ? L?nge des l?ngeren Objektes ???????? ist kein Vielfaches der L?nge des k?rzeren Objektes Browse[1]> str(TotalVector) ?int [1:10308] 3032 3048 3075 2978 3026 3012 2933 2987 3063 3038 ... Browse[1]> str(datalist2[[1]]$dataset$Results[[j]]$Results[[time]]$Sweep) ?int [1:10307] 2 1 3 1 5 6 3 1 0 2 ... as you can see the two vectors differ only in one element. As the sample is quite large it would be the same if I ignore the one extra element. There are times though that the missing elements can be 2 or 3 (but always the number is small enough so to be ignored) The major concern is that this "difference" can be either on the fist vector or either on the second vector. If I try to solve that with simple if statements the code gets too much of spaghetti... Is there a simple way when there is this length difference either to a. Ignore the extra elements -or- b. Add the elements missing to the vector with the smaller length( one can just duplicate some of the existing values to reach the needed length) How I can do either a or b? I would like to thank you in advance for your help Regards Alex ??? [[alternative HTML version deleted]] ______________________________________________ R-help at r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
Hi Your description is quite long but almost uninformative about what you really want. You do not say which values you want to sum but you say it is completely equal which value you want to add to what and what shall be the final vector length Based on this I would just use simple "+" x<-1:10 y<-1:9 x+y [1] 2 4 6 8 10 12 14 16 18 11 Warning message: In x + y : longer object length is not a multiple of shorter object length warning message is not an error and tells you that the shorter vector is recycled e.g. 1,2 or 3 elements are used twice for the calculation. Therefore the last value is 11 which is 10 from x vector + 1 from y vector. If you have some other constrains and failed to tell us please do it to get some better suited answer. Regards Petr> > Dear all, > in one part of my code I want to sum two vectors element-wise > the problem is that either the 1st vector or the 2nd vector always have > one or two less elements > > example of my problem > > In TotalVector +(datalist2[[1]]$dataset$Results[[j]]$Results[[time]]$Sweep) :> L?nge des l?ngeren Objektes > ist kein Vielfaches der L?nge des k?rzeren Objektes > Browse[1]> str(TotalVector) > int [1:10308] 3032 3048 3075 2978 3026 3012 2933 2987 3063 3038 ... > Browse[1]>str(datalist2[[1]]$dataset$Results[[j]]$Results[[time]]$Sweep)> int [1:10307] 2 1 3 1 5 6 3 1 0 2 ... > > > as you can see the two vectors differ only in one element. As the sample> is quite large it would be the same if I ignore the one extra element. > There are times though that the missing elements can be 2 or 3 (butalways> the number is small enough so to be ignored) > > > The major concern is that this "difference" can be either on the fist > vector or either on the second vector. If I try to solve that withsimple> if statements the code gets too much of spaghetti... Is there a simpleway> when there is this length difference > > > either to > > > a. Ignore the extra elements > -or- > > b. Add the elements missing to the vector with the smaller length( onecan> just duplicate some of the existing values to reach the needed length) > > How I can do either a or b? > > I would like to thank you in advance for your help > > Regards > Alex > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guidehttp://www.R-project.org/posting-guide.html> and provide commented, minimal, self-contained, reproducible code.
Is the Index of what you cut off or add unimportant or do you have indices on which to compare them? If you just want to have the same length, not depending on any indices: v1<-1:9 v2<-1:10 minlength<-min(length(v1),length(v2)) v1[1:minlength]+v2[1:minlength] If indices are important: names(v1)<-1:9 names(v2)<-1:10 df1<-data.frame(v1,n=names(v1)) df2<-data.frame(v2,n=names(v2)) merge(df1,df2,by.x="n",by.y="n") rowSums(merged[,-1]) On 03.08.2012, at 15:13, Alaios wrote:> Dear all, > in one part of my code I want to sum two vectors element-wise > the problem is that either the 1st vector or the 2nd vector always have one or two less elements > > example of my problem > > In TotalVector + (datalist2[[1]]$dataset$Results[[j]]$Results[[time]]$Sweep) : > L?nge des l?ngeren Objektes > ist kein Vielfaches der L?nge des k?rzeren Objektes > Browse[1]> str(TotalVector) > int [1:10308] 3032 3048 3075 2978 3026 3012 2933 2987 3063 3038 ... > Browse[1]> str(datalist2[[1]]$dataset$Results[[j]]$Results[[time]]$Sweep) > int [1:10307] 2 1 3 1 5 6 3 1 0 2 ... > > > as you can see the two vectors differ only in one element. As the sample is quite large it would be the same if I ignore the one extra element. > There are times though that the missing elements can be 2 or 3 (but always the number is small enough so to be ignored) > > > The major concern is that this "difference" can be either on the fist vector or either on the second vector. If I try to solve that with simple if statements the code gets too much of spaghetti... Is there a simple way when there is this length difference > > > either to > > > a. Ignore the extra elements > -or- > > b. Add the elements missing to the vector with the smaller length( one can just duplicate some of the existing values to reach the needed length) > > How I can do either a or b? > > I would like to thank you in advance for your help > > Regards > Alex > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code.