Hi Tammy,
I suspect that the first 4 digits compose the year, so with
Year_Month<-c(2010*100+9:11,2011*100+1:2)
#check composition
Year_Month
ym<-(Year_Month%/%100*12+Year_Month%%100)
ym-ym[1]
should give the difference in months.
Differences in Days are a bit trickier, since not all months have an
equal number of days. Something like
xd<-as.Date(paste(Year_Month%/%100,Year_Month%%100,"01",sep="-"))
xd-xd[1]
deals with that.
Cheers
Am 01.06.2012 13:31, schrieb Tammy Ma:>
> HI, R-Users:
>
> I got a questions. have been struggling so long time....
>
> I have this data:
>
>> m1$Year_Month
> 201009 201010 201011 201101 201102
>> min(m1$Year_Month)
> 201009
>
> I want to calculate the following two answers, how do I program it?
>
>> difference in Month?????
> [1] 0 1 2 4 5
>
>> difference in Days?????
> 0 31 61 ....
>
> Thank you in advance!!!
>
> Tammy
>
> [[alternative HTML version deleted]]
>
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