General goal: Write R code to find the inverse matrix of an nxn positive definite symmetric matrix. Use solve() to verify your code works. Started with a 3x3 matrix example to build the code, but something dosen't seem to be working. I just don't know where I am going wrong. ##Example matrix I found online A<-c(4,1,-1,1,2,1,-1,1,2) m<-matrix(A,nrow=3,ncol=3) ##Caculate the eigen vectors and eigenvalues E<-eigen(m, sym=TRUE) Q<-E$vectors V<-E$values n<-nrow(m) ##normalize the eigenvectors for(i in 1:n){ Q[,i]<-Q[,i]/sqrt(sum(Q[,i]^2)) } ##verify dot product of vectors are orthogonal sum(Q[,1]*Q[,2]) sum(Q[,1]*Q[,3]) sum(Q[,2]*Q[,3]) ##Begin creating QDQ^T matrix. Where Q are orthonormal eigenvectors, and D is a diagonal matrix with 1/eigenvalues on the diagonal. and Q^T is the transpose of Q. R<-t(Q) D<-mat.or.vec(n,n) for(i in 1:n) { D[i,i]<-1/V[i] } P<-Q*D*R ## P should be the inverse of the matrix m. Check using solve(m) ## solve(m) does not equal P? Any ideas of what I am missing/not understanding? -- View this message in context: http://r.789695.n4.nabble.com/Inverse-matrix-using-eigendecomposition-tp4188673p4188673.html Sent from the R help mailing list archive at Nabble.com.
wwreith wrote> > General goal: Write R code to find the inverse matrix of an nxn positive > definite symmetric matrix. Use solve() to verify your code works. > > Started with a 3x3 matrix example to build the code, but something dosen't > seem to be working. I just don't know where I am going wrong. > > ##Example matrix I found online > A<-c(4,1,-1,1,2,1,-1,1,2) > m<-matrix(A,nrow=3,ncol=3) > > ##Caculate the eigen vectors and eigenvalues > E<-eigen(m, sym=TRUE) > Q<-E$vectors > V<-E$values > n<-nrow(m) > > ##normalize the eigenvectors > for(i in 1:n){ > Q[,i]<-Q[,i]/sqrt(sum(Q[,i]^2)) > } > > ##verify dot product of vectors are orthogonal > sum(Q[,1]*Q[,2]) > sum(Q[,1]*Q[,3]) > sum(Q[,2]*Q[,3]) > > ##Begin creating QDQ^T matrix. Where Q are orthonormal eigenvectors, and D > is a diagonal matrix with 1/eigenvalues on the diagonal. and Q^T is the > transpose of Q. > > R<-t(Q) > D<-mat.or.vec(n,n) > for(i in 1:n) { > D[i,i]<-1/V[i] > } > P<-Q*D*R > > ## P should be the inverse of the matrix m. Check using > > solve(m) > > ## solve(m) does not equal P? Any ideas of what I am missing/not > understanding? >Homework questions are not answered. But to give you a hint: look in the "An Introduction to R" manual Chapter 5 "Array and Matrices" especially section 5.7 "Matrix facilities". (http://cran.r-project.org/doc/manuals/R-intro.html) You should be able to work out what's wrong in your script (a single statement). Berend -- View this message in context: http://r.789695.n4.nabble.com/Inverse-matrix-using-eigendecomposition-tp4188673p4188885.html Sent from the R help mailing list archive at Nabble.com.
Sorry but I am not a student, at least not since 2007. However I am performing grunt work for a someone with a Ph.D. so it does remind me of the student days. I just have a pay check instead of student loans. -- View this message in context: http://r.789695.n4.nabble.com/Inverse-matrix-using-eigendecomposition-tp4188673p4190557.html Sent from the R help mailing list archive at Nabble.com.