Dear Vincy,
Try this:
C[is.nan(C)] <- 0
HTH,
Ivan
Le 2/28/2011 13:10, Vincy Pyne a ?crit :> Dear R helpers
>
> I seem to have one trivial problem but can't find solution to it.
>
> Suppose I have following input.
>
> A = c(1, 3, 0, 5, 8) # 3rd element is 0
> B = c(100, 30, 0, 25, 40) # 3rd element is 0
>
> C = A/B
>
>> C
> [1] 0.01 0.10 NaN 0.20 0.20
>
> Obviously, I can't divide 0/0 and hence NaN. My problem is how to
replace this NaN say by 0.
>
> So that I can have C as
>
> C = c(0.01, 0.10, 0, 0.20, 0.20)
>
> I tried the replace command but can't get rid of NaN.
>
> Kindly guide.
>
> Vincy
>
>
>
> [[alternative HTML version deleted]]
>
>
>
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--
Ivan CALANDRA
PhD Student
University of Hamburg
Biozentrum Grindel und Zoologisches Museum
Abt. S?ugetiere
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+49(0)40 42838 6231
ivan.calandra at uni-hamburg.de
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