karmakiller
2010-Dec-29 00:01 UTC
[R] using lapply and split to plot up subsets of a vector
Hi, I would like to be able to plot data from each of the sp.id on individual plots. At the moment I can plot all the data on one graph with the following commands but I cannot figure out how to get individual graph for each sp.id. i<- function(df)plot(lnbm,ln.o2con,data=df) j<- lapply(split(one,one$sp.id),i) I have searched on the net and through the threads here but I cannot find anything that matches what I am trying to do. Any help would be greatly appreciated. Thanx -- View this message in context: http://r.789695.n4.nabble.com/using-lapply-and-split-to-plot-up-subsets-of-a-vector-tp3166634p3166634.html Sent from the R help mailing list archive at Nabble.com.
Phil Spector
2010-Dec-29 00:15 UTC
[R] using lapply and split to plot up subsets of a vector
The data= argument to plot only makes sense if the first
argument is a formula. So if you change the plot command
in your function to
plot(ln.o2con~lnbm,data=df)
you might get what you want. But I would suggest you take a
look at the plot produced by
library(lattice)
xyplot(ln.o2con~lnbm|sp.id,data=one)
which might be more useful.
- Phil Spector
Statistical Computing Facility
Department of Statistics
UC Berkeley
spector at stat.berkeley.edu
On Tue, 28 Dec 2010, karmakiller wrote:
>
> Hi,
>
> I would like to be able to plot data from each of the sp.id on individual
> plots. At the moment I can plot all the data on one graph with the
following
> commands but I cannot figure out how to get individual graph for each
sp.id.
>
> i<- function(df)plot(lnbm,ln.o2con,data=df)
> j<- lapply(split(one,one$sp.id),i)
>
> I have searched on the net and through the threads here but I cannot find
> anything that matches what I am trying to do. Any help would be greatly
> appreciated.
>
> Thanx
> --
> View this message in context:
http://r.789695.n4.nabble.com/using-lapply-and-split-to-plot-up-subsets-of-a-vector-tp3166634p3166634.html
> Sent from the R help mailing list archive at Nabble.com.
>
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