On Oct 5, 2010, at 8:41 AM, Alaios wrote:
> Hello everyone
> I need some advice if the following might be easier implemented.
>
> There are n matrixes
>
> each matrix needs to calculate one value for the rest n-1 matrixes
> (but not for
> itself). I implemented this one by
>
> two nested loops
>
> for (i in c(1:length(CRX))) {
>
> for (j in c(1:length(CRX)))
> if (i!=j)
> # where i and j are the two indexes. If i==j then is the same matrix.
> calculations()
> }
>
>
> Do you think there might be a more efficient R-wise way to implement
> this?
Does the result of "calculations()" depend on the order of the two
selected matrices? If not, then you are doing twice as many
calculations() as necessary and could use a test like:
if (i < j) # rather than if (i != j)
You could also create 2 way combinations with the combn function, but
I don't know if that would improve the speed (and I suspect the loop
is just as fast).
What does performance profiling tell you about where most of the cpu
time is being spent?
--
David.
>
> I would like to thank you in advance for your help
>
> Best Regards
> Alex
>
>
>
>
> [[alternative HTML version deleted]]
>
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David Winsemius, MD
West Hartford, CT