similar to: Make a loop more efficient

Hello everyone. I am using ggplot and I need some help to merge these two plots into one. plot_CR<-function(x,y,agentid,CRagent){   library(ggplot2)     agent<-CRagent[[agentid]] # To make following expression shorter   ggplot((data.frame(x=CRX,y=CRY,sr=agent$sr)))+   geom_point(aes(x,y,colour=cut(sr,c(0,-10,-20,-30,-40,-50,-60,-70,-80))))+   geom_text(aes(x,y,color=cut(sr,

Dear all, I have a data frame that is created like that data.frame(x=CRX[-1],y=CRY[-1],z=CRagent[[1]]$sr) the output looks like 45 116 162 -30.89105988567164 46 128  79 -42.66296679571184 47 180 195 -30.45626175641315 48 114  83 -45.26843476475688 49 118  73 -46.85389245327003 How can I select only the rows that their third column is higher that -45? This will return the following 116 162

try with an unc path and not a drive letter. if you get the admin auth you loose the drive letter. greetz, louis > Op 7 jan. 2016 om 20:37 heeft Mike <1100100 at gmail.com> het volgende geschreven: > > Version 4.1.19-SerNet-RedHat-11.el7 on CentOS 7.1503 > > Trying to install a software app on a domain user's windows client (Win 7 > Pro). > The user and

Hi, i am working on a problem where i need to compute the products of all possible combinations of size m of the elements of a vector. I know that this can be achieved using the function combn(), e.g.: > vector <- 1:6 > combn(x = vector, m = 3, FUN = function(y) prod(y)) In my case the vector has 2000 elements and i need to compute the values specified above for m = 32. Using combn() i

Hi all, My old and stable backup script don't work anymore. It's based on smbclient's tar command using crX parameters for creating archive, excluding files based on basic regular expressions. The box is running Fedora core 2, fully updated: kernel-2.6.8-1.521 samba-common-3.0.7-2.FC2 samba-client-3.0.7-2.FC2 The error is easily reproducible: smbclient //ntpdc/share -A credfile \ -c

that was a stupid answer, sorry, i did read it correctly. post your smb.conf (sanitized) so we can have a look what we are talking about. > Op 7 jan. 2016 om 20:56 heeft L.P.H. van Belle <belle at bazuin.nl> het volgende geschreven: > > try with an unc path and not a drive letter. > if you get the admin auth you loose the drive letter. > > greetz, > louis >

Hello! I've a problem with the combn function and a set of vector. I would like to make a simple combination where, instead of scalars, i would like to combine vector, in order to form matrixes. In other words, i have nineteen 6-items vectors (for example coef1-coef19), that i would like to combine in n!/k!(n-k)! 6x6 matrixes. I tried with a code like this mma <-

Hello everyone, Could you please help me find out if R supports matrixes inside matrixes? This is what I would like to do I have an area map of humidity per km. I would like at every cell to keep also information about the height of this area, the current temperature etc. Is something like that supported? I would like to thank you in advance for your help Best Regards Alex

On Tue, Aug 23, 2005 at 03:10:45PM +1000, openssh-unix-dev-request at mindrot.org wrote: > Date: Fri, 19 Aug 2005 17:56:19 +1000 > From: Darren Tucker <dtucker at zip.com.au> > Subject: Re: OpenSSH sget/sput suggestion > To: CRX Driver <crxssi at hotmail.com> > Cc: openssh-unix-dev at mindrot.org > Message-ID: <430590A3.1090506 at zip.com.au> > Content-Type:

Hi List, I'm hoping to get opinions for enhancing the efficiency of the following code designed to take a vector of probabilities (outcomes) and calculate a union of the probability space. As part of the union calculation, combn() must be used, which returns a matrix, and the parallelized version of lapply() provided in the multicore package requires a list. I've found that

I have a repetative task in R and i'm trying to find a more efficient way to perform the following task. lst <- list(roots = c("car insurance", "auto insurance"), roots2 = c("insurance"), prefix = c("cheap", "budget"), prefix2 = c("low cost"), suffix = c("quote", "quotes"),

Hi All, My question is in regards to an error generated when using randomForest in R. Is there a special way to format the data in order to avoid this error, or am I completely confused on what the error implies? "Error in randomForest.default(m, y, ...) : Can not handle categorical predictors with more than 32 categories." This is generated from the command line: >

Hello. I want to print the value a matrix has. The matrix's size is not too big (100*100 cells). I tried print(matrixname) but as it does not fit very well on my screen R splits it into several small matrixes that do overflow my screen. IS it possible somehow to display this matrix as one (even if this needs to go fullscreen) . There might be some function for that like plot cells or

Dear all I have two 10*10 matrixes and I would like to compare theirs contents. By the word content I mean to check visually (not with any mathematical formulation) how similar are the contents. I also know edit that prints my matrix in the scree but still one edit blocks the prompt to launch a second edit() screen. What is the best way to compare these two matrices? I would like to thank you

Hello, I'm looking for an efficient function for calculating partial correlations. I'm currently using the pcor.test () function, which is equivalent to the cor.test() function, and can receive only single vectors as input. I'm looking for something which is equivalent to the cor() function, and can receive matrixes as input (which should make the calculations much more efficient).

Hello everyone, I need some help with lists inside lists (a good way to emulate a struct)\ Assume that there is a small list called fred: fred <- list(happy = 1:10, name = "squash") and a big list called bigfred that includes fred list 5 times bigfred <- rep(fred,5) Is it possible somehow to index all these sublists(fred) inside bigfred with a more direct way like this:

Hi, anyone interested in this: I tried to simply this loop with lapply or something but haven't figured it out: mapt = c("203929_s_at", "203930_s_at", "203928_x_at", "206401_s_at") mapt.combn <- lapply(1:4, function(i) combn(mapt, i)) out = list() k = 1 for (i in 1:length(mapt.combn)){ for (j in 1:ncol(mapt.combn[[i]])){ out[[k]] =

On Mon, 11 Jun 2012 08:56:21 -0700 Jakob Stoklund Olesen <stoklund at 2pi.dk> wrote: > > On Jun 11, 2012, at 8:07 AM, Hal Finkel wrote: > > > Also, I think the following might work well: If we add a special > > kind of register dependency called a 'remembered' register. This is > > not a real dependency meaning that that the instruction does not >

Hi All, In the script below, the importance measure for column 4 (ie MeanDecreaseGini) indicated "Inf" for V7. Running the getTree command showed that "V7" had been selected at least twice in one of the trees for Random Forest. So the "Inf" command was not generated as a result of dividing the sum of the decreases by 0. Any suggestions on what may be causing the

Dear all, I would like to ask you if R can produce any kind of sound. It would be useful when code execution stops R to notify me by playing some sound. Is that possible in R? I would like to thank you in advance for your help Best Regards Alex