Hi, I have dates in this kind of format (day, month, year):> dput(head(dates, 10))c("6.4.7", "29.12.98", "19.10.91", "20.6.92", "2.9.3", "23.6.3", "13.7.93", "23.3.7", "26.6.95", "15.2.10") So, as you can see, there is no century. How can I change this character data into dates? Any help would be most appreciated. -J
Actually I found it:> as.Date(strptime(dates, "%d.%m.%y"), "%Y-%m-%d")[1] "2007-04-06" "1998-12-29" "1991-10-19" "1992-06-20" "2003-09-02" "2003-06-23" "1993-07-13" "2007-03-23" "1995-06-26" "2010-02-15" -J 2010/3/12 johannes rara <johannesraja at gmail.com>:> Hi, > > I have dates in this kind of format (day, month, year): > >> dput(head(dates, 10)) > c("6.4.7", "29.12.98", "19.10.91", "20.6.92", "2.9.3", "23.6.3", > "13.7.93", "23.3.7", "26.6.95", "15.2.10") > > So, as you can see, there is no century. How can I change this > character data into dates? Any help would be most appreciated. > > -J >
Dear all, how can i get rid of the text in the calibration plot below the x-axis. thanks Paaveen _________________________________________________________________ Check your Hotmail from your phone. [[alternative HTML version deleted]]
On Mar 12, 2010, at 4:14 PM, paaventhan jeyaganth wrote:> > > Dear all, > > how can i get rid of the text in the calibration plot below the x- > axis.http://en.wikipedia.org/wiki/Correction_fluid>David Winsemius, MD West Hartford, CT
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