R help - Sep 2009 - How to generate a matrix where each row (or column) is the same vector?

Hi,

I can use the following code to generate a matrix, each column of
which is 'x'. But I have to specify '5' twice in the second
command. I
am wondering if there is a better way to do it.
> x=1:10
> matrix(rep(x,5),nc=5)
> t(matrix(rep(x,5),nc=5))
Regards,
Peng

On 09/17/2009 04:02 PM, Peng Yu wrote:
>
> Hi,
>
> I can use the following code to generate a matrix, each column of
> which is 'x'. But I have to specify '5' twice in the second
command. I
> am wondering if there is a better way to do it.
>
>> x=1:10
>> matrix(rep(x,5),nc=5)
>> t(matrix(rep(x,5),nc=5))
>
> Regards,
> Peng
This works for me:

 > do.call( cbind, rep( list( x ), 5 ) )
 > do.call( rbind, rep( list( x ), 5 ) )

Romain

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On 09/17/2009 04:02 PM, Peng Yu wrote:
>
> Hi,
>
> I can use the following code to generate a matrix, each column of
> which is 'x'. But I have to specify '5' twice in the second
command. I
> am wondering if there is a better way to do it.
>
>> x=1:10
>> matrix(rep(x,5),nc=5)
>> t(matrix(rep(x,5),nc=5))
>
> Regards,
> Peng
Or this ;

 > matrix(rep(x,5),nr=length(x))

Romain

-- 
Romain Francois
Professional R Enthusiast
+33(0) 6 28 91 30 30
http://romainfrancois.blog.free.fr
|- http://tr.im/yw8E : New R package : sos
|- http://tr.im/y8y0 : search the graph gallery from R
`- http://tr.im/y8wY : new R package : ant

Or:

replicate(5, 1:10)

On Thu, Sep 17, 2009 at 11:02 AM, Peng Yu <pengyu.ut at gmail.com>
wrote:
> Hi,
>
> I can use the following code to generate a matrix, each column of
> which is 'x'. But I have to specify '5' twice in the second
command. I
> am wondering if there is a better way to do it.
>
>> x=1:10
>> matrix(rep(x,5),nc=5)
>> t(matrix(rep(x,5),nc=5))
>
> Regards,
> Peng
>
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