Hi. I am sure there is a better way in R to do this then using a loop but I
am new to it and not sure what to do. I think it might be something about
using a function as an argument but not sure.
I have a 1 x 2000 vector TS2 which has entries from the set {x: x is in Z
and 0<x<8} (where Z is the set of Integers).
Then I also have a 5050 x 7 matrix called 'perm' whose entries are also
from
the set {x: x is in Z and 0<x<8}
I want to construct the following transformation of TS2 which will still be
a vector of size 1 x 2000 and which I will call 'newTS2' such that:
newTS2 =(perm[100.TS2[1]]. perm[100.TS2[2]]. perm[100.TS2[3]]. ... ,
perm[100.TS2[2000]])
Is there a nice way to do this without a loop?
Thank you.
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onyourmark wrote:> Hi. I am sure there is a better way in R to do this then using a loop but I > am new to it and not sure what to do. I think it might be something about > using a function as an argument but not sure. > > I have a 1 x 2000 vector TS2 which has entries from the set {x: x is in Z > and 0<x<8} (where Z is the set of Integers). > > Then I also have a 5050 x 7 matrix called 'perm' whose entries are also from > the set {x: x is in Z and 0<x<8} > > I want to construct the following transformation of TS2 which will still be > a vector of size 1 x 2000 and which I will call 'newTS2' such that: > > newTS2 =(perm[100.TS2[1]]. perm[100.TS2[2]]. perm[100.TS2[3]]. ... ,Perhaps you can explain what the last line is supposed to do? This is invalid R code and also not a known mathematical notation for me .... Uwe Ligges> perm[100.TS2[2000]]) > > Is there a nice way to do this without a loop? > > Thank you.