R help - Jul 2008 - rm(l*)

Dear Rusers,

how can I designate various objects the names of which start (or end) with
the same letter to remove them all together?

For instance:
> ls()
"a","b","c","l1","l2","x"
> rm(list=ls("l*"))
> ls()
"a","b","c",""x"

Is there some parallel to the MySQL query: where col1 like "l%"

Thanks a lot in advance,
Friderike


	[[alternative HTML version deleted]]

Maybe there is a simpler way, but this works fine:
> l1 <- 1
> l2 <-2
> m <-10
> ls()
[1] "l1" "l2" "m" 
> rm(list=grep("^l.*", ls(), value=TRUE))
> ls()
[1] "m"
> 
You can supply a regular expression to grep.

Gabor

On Mon, Jul 14, 2008 at 10:45:13AM +0200, Oehler, Friderike (AGPP)
wrote:
> Dear Rusers,
> 
> how can I designate various objects the names of which start (or end) with
> the same letter to remove them all together?
> 
> For instance:
> > ls()
>
"a","b","c","l1","l2","x"
> > rm(list=ls("l*"))
> > ls()
> "a","b","c",""x"
> 
> Is there some parallel to the MySQL query: where col1 like "l%"
> 
> Thanks a lot in advance,
> Friderike
> 
> 
> 	[[alternative HTML version deleted]]
> 
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-- 
Csardi Gabor <csardi at rmki.kfki.hu>    UNIL DGM