search for: csardi

Hi, Given a simple example, test <- matrix(c(0.1, 0.2, 0.1, 0.2, 0.1, 0.1, 0.3, 0.1, 0.1), 3, 3) How to generate row indexes for which their corresponding row values are less than or equal to 0.2 ? For this example, row 2 and 3 are the correct ones. Thanks [[alternative HTML version deleted]]

Hi, I have a simple beginner's question on removing a list of objects. Say I have objects C243.Daily1, C243.Daily2...C243.Daily5 in my workspace. I'd like to remove these without using rm five times. So I write. > a <- list(paste("C243.Daily",sep="",1:5)) > rm(a) Obviously this wouldn't work, as it would only remove the object a. But is there any way

Hello I am a relatively new user of R and am struggling to use the 'network' package. I have a correlation matrix (produced using 'cor'), and want to draw a network where each item showing correlation above a threshold (say 0.5) is joined by a green line, and each item showing correlation below a threshold (say -0.5) is joined by a red line. Does anyone have any hints of how to

...hich basically means that the rowSums() in the base package is called, not the S4 generic in the Matrix package. Why is that? Is there any way to work around this problem, without depending on Matrix? I am doing this on R 2.14.0, x86_64-apple-darwin9.8.0. Thank You, Best Regards, Gabor -- Gabor Csardi <csardi at rmki.kfki.hu>? ?? MTA KFKI RMKI

I'm just curious. Why making "if" generic is even more dangerous? Best, Da On Sat, Mar 4, 2017 at 1:22 PM, G?bor Cs?rdi <csardi.gabor at gmail.com> wrote: > `!` is a generic, `if` is not. You can define an `if` that is generic, > but this might be even more dangerous.... > > ? `if` <- function(a, b, c) UseMethod("if") > ? `if.default` <- function(a,b,c) base::`if`(a, b, c) > ? `if.foo` &...

Dear colleagues, I'm trying to have a look at the Assortative and Disassortative ( http://en.wikipedia.org/wiki/Assortative_mixing) of the network I have. But it seems that the igraph hasn't mentioned that yet. I have to get the in/out degree of the vertices of each edge and calculate the Pearson's Correlation coefficient which seems to be quite a huge task for me. :( So I wonder if

.... an alternative would be to ask them to depend on the exact current version of the package. This is an easier solution, but it won't give people the opportunity to load both versions of the package at the same time, if they want to run their old code. Thank You, Best Regards, Gabor -- Gabor Csardi <csardi.gabor at gmail.com> Dept. Statistics, Harvard University

Dear List, i know there are some solutions for this in the archive, but they're not very good for numeric matrices, since they usually convert rows/columns to character strings. Is there an easy way to do $subject for numeric matrices properly, or i need to do it by hand? Thanks, Gabor

...plot: function(x, ...) plot.communities: function(communities, graph, colbar, col, mark.groups, layout, edge.color, ...) But actually, the signature of plot() seems to be > plot function (x, y, ...) [...] I am confused. What am I missing? Thanks, Best Regards, Gabor -- Gabor Csardi <Gabor.Csardi at unil.ch> UNIL DGM

Was this resolved upstream or is this something that R should/could fix? If the latter, could this also go into the "emergency release" R 4.0.2 that is scheduled for 2020-06-22? My $.02 /Henrik On Sun, May 31, 2020 at 8:13 AM G?bor Cs?rdi <csardi.gabor at gmail.com> wrote: > > Btw. it would be also possible to create a macOS R installer that > embeds a static or dynamic libcurl with Secure Transport, instead of > the Apple default LibreSSL. > > This might be too late for R 4.0.1, I don't know. > > Gabor > &...

Greetings, R-ians: I would like to know which version or R was used to create a given package. I think I remember seeing that topic discussed recently but cannot find it among my notes. Can anyone tell me how to determine which version of R created a package? Thanks. Charles Annis, P.E. <mailto:Charles.Annis@StatisticalEngineering.com> Charles.Annis@StatisticalEngineering.com

Hello R Help Team, I have created graph from weighted adjecency matrix .Is there a way I can find highly connected nodes in Igraph like the Package RBGL does. nathan -- View this message in context: http://www.nabble.com/Highly-Connected-Nodes-in-Igraph-tp22377522p22377522.html Sent from the R help mailing list archive at Nabble.com.

...ermissions to any directory on the system. It seems that I need to modify the R source code for this, to make R start without creating a temporary directory. So far, so good. But should I expect any more complications? Does R really need the temporary directory that much? Thanks, Gabor -- Gabor Csardi <Gabor.Csardi at unil.ch> UNIL DGM

useR's, Consider: y <- c(20, 25, 30) > m <- matrix(c(0.0,1,NA,0.5,1.25,0.75, 0.5, NA, > NA),byrow=TRUE,nrow=3,ncol=3) > m [,1] [,2] [,3] [1,] 0.0 1.00 NA [2,] 0.5 1.25 0.75 [3,] 0.5 NA NA For each numeric value, I want to replace them with their corresponding y-value. The result should look like (here, each row represents a variable rather than the columns):

On Sat, May 30, 2020 at 11:32 PM G?bor Cs?rdi <csardi.gabor at gmail.com> wrote: [...] > Btw. why does this affect openssl? That root cert was published in > 2010, surely openssl should know about it? Maybe libcurl / openssl > only uses the chain provided by the server? Without trying to use an > alternate chain? Yes, indeed it seems t...

I'm trying to draw an arrow with a curved shaft on the graph as a straight one looks messy on a detailed graph. I've looked in arrows but it doesn't seem to give an option. larrows doesn't look much more promising. I had a look in the archive and couldn't find anything. Any thoughts? Thanks Paul -- View this message in context:

Dear everybody! I am making a graph in R and employ pstoedit to expot the .pdf-output to .svg. When I open the .svg with firefox I get the .svg-code shown wit the following header: "Mit dieser XML-Datei sind anscheinend keine Style-Informationen verkn?pft. Nachfolgend wird die Baum-Ansicht des Dokuments angezeigt." Which information should how be included? Thank you in advance. Yours,

Hallo, I am running R-2.6. on Windows. I have a code which uses library(convert). Can anyone tell me which package I need to install to run this code. Everytime I receive the error message library (convert) not found. Thanks, Corinna

Hi, how can I replace NA value with 0: 1991 217 119 103 109 137 202 283 240 146 NA 1992 270 174 149 144 166 239 278 237 275 NA 1993 146 111 104 89 98 131 153 148 175 NA 1994 177 123 146 124 121 200 266 191 240 106 1995 145 98 95 89 95 130 183 161 164 129 1996 145 98 89 90 93 138 158 131 161 161 1991 217 119 103 109 137 202 283 240 146 0 1992 270 174 149 144 166 239 278 237

Hi all, I'm very new to R and read a few tutorials, however I'm having difficulty trying to figure out how to plot a minimum spanning tree. I have a csv file that contains an n-by-n matrix of distances between strains of bacteria called matrix.csv. Looks like: id,strain1, strain2,strain3 strain1,0,.2,.8 strain2,.3,0,.7 strain3,.4,.6,0 I've been messing around with some information