R help - May 2008 - how to bind lists recursively

Dear all,

I want to create a list that contains 0,1,2,3, ..., 10000 as its elements. I 
used the following code, which apparently doesn't work very well.

a <- 0
for(i in 1:10000) {
    a <- list(a, i)
}

The result is not what I wanted. So how to create the bind lists recursively 
so that the last element would be the newly added one while the previous 
elements all remain the same?

Thanks!
Daniel

On May 27, 2008, at 10:43 PM, Daniel Yang wrote:
> Dear all,
>
> I want to create a list that contains 0,1,2,3, ..., 10000 as its  
> elements. I used the following code, which apparently doesn't work  
> very well.
>
> a <- 0
> for(i in 1:10000) {
>    a <- list(a, i)
> }
>
> The result is not what I wanted. So how to create the bind lists  
> recursively so that the last element would be the newly added one  
> while the previous elements all remain the same?
Hm, for the particular problem you are asking, I think that:

as.list(0:10000)

should do the trick. I m guessing it might not work for the real  
application you had in mind.

If you insist on the for loop, then you can do the following:

a <- list(0)
for(i in 1:10000) {
    a <- c(a, i)
}

Though it's much smaller. In general, it is better to assign the  
correct size to the list to begin with, I believe.
> Thanks!
> Daniel
Haris Skiadas
Department of Mathematics and Computer Science
Hanover College

On 28/05/2008, at 2:43 PM, Daniel Yang wrote:
> Dear all,
>
> I want to create a list that contains 0,1,2,3, ..., 10000 as its  
> elements. I used the following code, which apparently doesn't work  
> very well.
>
> a <- 0
> for(i in 1:10000) {
>    a <- list(a, i)
> }
>
> The result is not what I wanted. So how to create the bind lists  
> recursively so that the last element would be the newly added one  
> while the previous elements all remain the same?
a <- list()
for(i in 1:10000) a[[i]] <- i

(The word ``bind'' is inappropriate.)

	cheers,

		Rolf Turner

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