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On 22/2/2023 2:30 ?.?., Aki Tuomi wrote: > Can you please try > > doveadm exec imap -u username_of_the_user > 1 LIST "" "*" > > and see if it is there? Here is the output: # doveadm exec imap -u userx * PREAUTH [CAPABILITY IMAP4rev1 SASL-IR LOGIN-REFERRALS ID ENABLE IDLE SORT SORT=DISPLAY THREAD=REFERENCES THREAD=REFS THREAD=ORDEREDSUBJECT MULTIAPPEND

Can you please try doveadm exec imap -u username_of_the_user 1 LIST "" "*" and see if it is there? Aki > On 22/02/2023 14:28 EET Nikolaos Milas <nmilas at noa.gr> wrote: > > > On 21/2/2023 9:56 ?.?., Aki Tuomi wrote: > > Can you enable mail_debug=yes, restart, ask the user to access the folder(s) and provide those logs? > > > > Hi

I don?t seem to have that install on my Debian machine. But I have done this: 1 LIST "" % * LIST (\HasNoChildren) "/" confirmed-spam * LIST (\HasChildren) "/" Archive * LIST (\HasNoChildren \Sent) "/" Sent * LIST (\HasChildren \Trash) "/" Trash * LIST (\HasNoChildren) "/" Spam * LIST (\HasChildren) "/" Archives * LIST

We defined a number of functions on lists which are not provided by the standard library. As with Char and String, let's extend List to add these new functions to a List pseudo-module (really Std_utils.List, but called List when you ‘open Std_utils’). The initial exported functions are all List functions from OCaml 3.11 + iteri + map...

Hi Timo, doveadm reports errors for \Noselect mailboxes. What I have: 1 LIST "" * * LIST (\HasNoChildren) "/" "Templates" * LIST (\HasChildren) "/" "INBOX" * LIST (\Noselect \HasChildren) "/" "INBOX/Lists" * LIST (\Noselect \HasChildren) "/" "INBOX/Lists/vmm" * LIST (\HasNoChildren) "/" "INBOX/Lists/vmm/users" * LIST (\HasNoChildren) "/" "INBOX/Lists/vmm/hg" * LIST (\Noselect \HasChildren) "/" "INBOX/Lists/Postfix"...

Hi, I'm trying to read a .mat file into R (2.11.1) with medium success so far. The file I have is a MATLAB 5.0 MAT-file exported from RiverSurveyor LIVE software (http://www.sontek.com/software.php). I have R.matlab and Rcompression installed and readMat() starts reading the file, as can be seen in verbose mode (hence medium success), but then gives the following error: Error in dim(matrix)

Hi: I have a table called clients and each client has many lists (a has_many and belongs_to has been created in the class. What I need to do is get a count of the rows in each list for each client. I was hoping I could do something like client.lists.count but it does not seem to work. Any suggestions? bruce

...ge writeable = Yes [DATA] path = /DATA --------------------------------------- Thanks for your help in advance George glsaly@hotmail.com Return-Path: <sean@digitalworkshop.net> Delivered-To: samba@samba.org Received: from hose.mail.pipex.net (hose.mail.pipex.net [158.43.128.58]) by lists.samba.org (Postfix) with SMTP id 6E9EF4474 for <samba@samba.org>; Sun, 3 Jun 2001 14:44:27 -0700 (PDT) Received: (qmail 3649 invoked from network); 3 Jun 2001 21:44:30 -0000 Received: from usered59.uk.uudial.com (HELO BRAVO) (62.188.10.238) by smtp-4.dial.pipex.com with SMTP; 3 Jun 2001...

...sensitive e-mail. Destination mailbox(es): "samba@samba.org" ******************* End of message ******************* -------------- next part -------------- Received: from 208.8.92.167 by jupiter.INSIDEAI.COM (InterScan E-Mail VirusWall NT); Sun, 19 Oct 2003 14:55:27 -0400 Received: from lists.samba.org ([66.70.73.150]) by release.musictelecom.com (Post.Office MTA v3.5.3 release 223 ID# 0-0U10L2S100V35) with ESMTP id com for <jkuo@musictelecom.com>; Sun, 19 Oct 2003 14:55:17 -0400 Received: from dp.samba.org (localhost [127.0.0.1]) by lists.samba.org...

I''m looking for an example of how one could write a dtrace probe that could follow something like a NULL terminated linked list. For example: struct list { struct list *next; void *data; }; struct list *list_root; Assuming I had "list_root" available, but I wanted to know how long the linked list is, how can I do this in a dtrace probe? If I had looping

...f you config is still the samba as i found in the list. On the member server, in smb.conf Change : realm = hq.kontrast To : realm = HQ.KONTRAST And whats in the krb5.conf of the member server? Greetz, Louis > -----Oorspronkelijk bericht----- > Van: samba [mailto:samba-bounces at lists.samba.org] Namens Oliver Werner via > samba > Verzonden: woensdag 28 september 2016 15:54 > Aan: Oliver Werner > CC: samba at lists.samba.org > Onderwerp: Re: [Samba] Samba Member NT_STATUS_NETWORK_SESSION_EXPIRED > > Any Ideas what i can test for fix the problem with kerberos...

# Hello, # I have a list with 6 categories and with different numbers of rows. # I would like to change each of them into a unique data frame in order to match # values with other data frames and perform some calculations. # Or I could make each category or list element have the same number of rows and create one large data.frame. # below is a creation of a sample list # I apologize for the

why the install is failing. Do in need to rpm -e on all the 2.07 packages??? Return-Path: <nikolaus@erlm.siemens.de> Delivered-To: samba@lists.samba.org Received: from atlantis.erlm.siemens.de (atlantis.erlm.siemens.de [212.114.202.14]) by lists.samba.org (Postfix) with ESMTP id B884C4278 for <samba@lists.samba.org>; Sun, 27 May 2001 22:05:52 -0700 (PDT) Received: from tcenter.erlm.siemens.de (tcenter.erlm.siemens.de [146.254....

Hello, I have a nested named list structure, like the following: x <- list( list( list(df1,df2) list(df3, list(df4,df5)) list(df6,df7))) with df1...d7 as data frames. Every data frame is named. Is there a way to get a specific named element in x? so, for example, x[[c("df5")]] gives me the data frame 5? Thank you in advance! Best, Friedericksen

...All workstations logon and mount the samba file services. We'd like to check if the problem could be solved by setting the oplock = false or any other tweaking is needed. Thank you very much! Vincent -- To unsubscribe from this list go to the following URL and read the instructions: http://lists.samba.org/mailman/listinfo/samba Return-Path: <liszli@freemail.hu> Delivered-To: samba@lists.samba.org Received: from legba.tvnet.hu (legba.tvnet.hu [195.38.96.20]) by lists.samba.org (Postfix) with ESMTP id 0FD5A4619 for <samba@lists.samba.org>; Thu, 31 May 2001 06:59:41 -0700 (PD...

Hi, I am working with lists whose terms are lists whose terms are lists. Although the real ones contain locuslink identifiers and GO annotations (I work with the Bioconductor GO) package, I have prepared an simplified example of what I have and what I would like to do with it: Imagine I have a list such as: tst.list<-...

...> Tel: +49 (0)89 748 99 - 127 > Fax: +49 (0)89 748 99 - 111 > Mob: +49 (0)172 89 86 401 > E-Mail: stefan.kaes@portax.com > Web: http://www.portax.com > -- > To unsubscribe from this list go to the following URL and read the > instructions: http://lists.samba.org/mailman/listinfo/samba > _______________________________________________________________________ In a world without walls and fences, who needs windows and gates? (SUN) Return-Path: <gcarter@valinux.com> Delivered-To: samba@samba.org Received: from Eng.Auburn.EDU (dns.eng.aub...

I have these tables set up like this: listings has_many :states <field>state_id [int] <other fields.... .............. .............> states belongs_to: listings <field>name <other fields.. ............... .................> In my view I have <%= listing.name %> have also tried listing.state_id.name , that didn''t seem to do the magic either. This

I have a list List(Sku=" ", Shape=1, Scale=3, DayOfYear=daylist) Note: picture daylist as c(2,3,4,3) it is a list with variable length. Then I have a list of lists al <- c(al, List(List(Sku=" ", Shape=1, Scale=3, DayOfYear=daylist)) Note: same comment on daylist as above. So far this creates a list of lists just how I want it. If I do al[1] I get each member and the variable length list 'daylist'. Now I want to export this list of list...

...ookup(names, "cat") to return 2 and lookup(names, "ant") to return 0 (or 5) i am currently doing this in a for loop with a break using identical(). however, since i call this function repeatedly, i am wondering whether there is a more efficient way of doing this. (2) combining lists: when lists are combined, the higher level list structure appears to be lost. what i mean is, suppose i have two lists with the same structure a <- list(name="foo", year=1989, grade="A"); b <- list(name="bar", year=2000, grade="B+"); then when i combine...