R help - Mar 2008 - esercizio

? stato filtrato un testo allegato il cui set di caratteri non era
indicato...
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Hey Flo,

I'm not entirely sure what you're problem is -- due to the language
thing,
probably -- but I think you want a function that will give you (or computes
in an intermediate step) the "edit distance" between strings.  There
is the
"sdists" function in the cba package that might help (it can give you
the
pairwise distances between a bunch of strings easily), or you can use the
"agrep" function to find approximate matches:
>max.edits <- list(all=1, substitutions=1, insertions=0, deletions=0)
>words <- c("casa", "cosa", "rosa")
>agrep(pattern="casa", x=words, max.distance=max.edits)
[1] 1 2

i.e. "casa" matches (within 1 letter substitution) the 1st and 2nd
elements
of the words vector.  "casa" is an approximate match to
"casa" and to "cosa"
but not "rosa" because that's two substitutions and we chose a max
of one.

- Mose

On Mon, Mar 3, 2008 at 8:47 AM, Flo <floah@yahoo.it> wrote:
> Ciao a tutti!
>  ho un problema con un esercizio in R.
>
>  In una lista devo trovare tutte le parole che si differenziano per una
> lettera da un'altra parola.
>  Esempio: per "casa": cosa, rosa...
>
>  C'è una formula generale da applicare a tutte le parole?
>  Grazie dell'aiuto, Flo
>
>
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