See
?aov
?lm
something like
lm(result~yourfactor1+yourfactor2+yourfactor3+yourfactor5,
data=yourdataframe)
or
aov(result~yourfactor1+yourfactor2+yourfactor3+yourfactor5,
data=yourdataframe)
but the exact structure of lm or aov construction depends on what you
want to test.
HTH
Petr
On 28 Jul 2006 at 21:43, dvrecko at sfu.ca wrote:
Date sent: Fri, 28 Jul 2006 21:43:38 -0700
From: dvrecko at sfu.ca
To: r-help at stat.math.ethz.ch
Subject: [R] DOE in R
Send reply to: dvrecko at sfu.ca
<mailto:r-help-request at stat.math.ethz.ch?subject=unsubscribe>
<mailto:r-help-request at stat.math.ethz.ch?subject=subscribe>
> Hi.
>
> I'm a student in a graduate program at Simon Fraser University in
> Canada.
>
> I am trying to run a simple screening experiment with some simulated
> data.
>
> I simply want to do an ANOVA of an experiemnt with 5 factors (4 have 2
> levels, the last has 3 levels) and 48 runs (ie, full factorial).
>
> The thing is that I have multiple observations for each level
> combination (run).
>
> So,
>
> 1) How do I do the anova based on the setup above?
>
> and
>
> 2) More importantly, because of convergence issues for my simulations,
> I will likely have an unequal number of observations for the 48 runs.
> How can I do this?
>
> Seems like a straightforward enough situation.
>
> I am trying to avaoid writing my own C code to do the analysis since I
> am working under some pretty tight time constraints.
>
> ANy help would be appreciated.
>
> Thanks very much.
>
> Dean Vrecko
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html and provide commented,
> minimal, self-contained, reproducible code.
Petr Pikal
petr.pikal at precheza.cz