search for: yourdatafram

Displaying 20 results from an estimated 26 matches for "yourdatafram".

Did you mean: yourdataframe
2009 Nov 16
5
Writing a data frame in an excel file
Hello, I am having trouble by using the write.table function to write a data frame of 4 columns and 7530 rows. I don?t know if I should just use a sep="\n" and change the .xls file into a .csv file. Thanks in advance ----- Anna Lippel new in R so be careful I should be asking a loooooooot of questions!:teeth: -- View this message in context:
2007 May 04
1
R question
I had a question about Random Forests. I have a text file with 10 dichotomous variables and a bivariate response vector. I read this file into R as a data frame, and then used the command "randomForest(Response ~., dataset, etc.." where "Response" is the column header of the response variable and "dataset" is the name of the data frame. I get an error that says
2010 Aug 04
1
Carriage return character issue
Hi all, I imported a file (in CSV format) into R for processing, then imported the result into MySQL. However, there are *carriage return* characters (hexadecimal: *0D*) that are appended to the characters in the last field of the table. i.e *\r* appended to the character values (as shown below) Before importing into MySQL: asdf After importing into MySQL: asdf*\r* ** ** Are there any options
2012 Mar 02
1
data frame of strings formatted
Hello, I have another question.... I have a data frame that looks like this: a b 2007-03-31 "20070514" "20070410" 2007-06-30 "20070814" "20070709" 2007-09-30 "20071115" "20071009" 2007-12-31 "20080213" "20080109" 2008-03-31 "20080514" "20080407" 2008-06-30
2006 Jul 29
1
DOE in R
Hi. I'm a student in a graduate program at Simon Fraser University in Canada. I am trying to run a simple screening experiment with some simulated data. I simply want to do an ANOVA of an experiemnt with 5 factors (4 have 2 levels, the last has 3 levels) and 48 runs (ie, full factorial). The thing is that I have multiple observations for each level combination (run). So, 1) How do I do
2010 Apr 27
4
Selecting rows based on contents of string
Hi there, I have a data frame with a column named "Flags", whose contents are strings containing any of the following characters, multiple characters allowed: A,B,C,D,E,F,G. Here is the head: GeocodeID PlaceID CountyCode CBSACode StateProvCode PropertyTypeGroupID Flags 1 0 0 0 0 AK 1 ABC 2
2012 May 02
2
selection by two unique variables
Dear Group, I am working with a large dataset where I need to select for each unique id the the unique lastpk row. Here is a sample subject: id wtdt wt lastpk 64050256 2010-09-18 275 2010-09-16 64050256 2010-09-19 277 2010-09-18 64050256 2010-09-20 272 2010-09-18 64050256 2010-09-21 277 2010-09-18 I want the result as:
2010 Dec 24
4
Removing rows with earlier dates
Hi all, I'm new to the list but have benfited from it quite extensively. Straight to my rather strange question: I have a data frame that contains mapping rules in this way: ACCOUNT, RULE COLUMNS, Effective Date The dataframe comes from a database that stores all dates. What I would like to do is to create a data frame with only the most recent rule for each account. In traditional
2010 Jan 13
4
a question about deleting rows
I have a file like this: id n1 n2 n3 n4 n5 n6 1 3 4 7 8 10 2 2 4 1 2 4 3 10 3 7 0 0 0 0 8 4 10 1 0 0 2 3 5 11 1 0 0 0 5 what I want to do is: only if n2=0 and n3=0 and n4=0 and n5=0 then delete the row. how can I do that? thank you, karena -- View this message
2017 Jun 01
0
Data import R: some explanatory variables not showing up correctly in summary
...e first case the duplicates probably represent cases in your source data (a spreadsheet?), where you have inadvertently put a space at the end of the label, e.g. "combination", and "combination ". The answers to both questions are easy to find with the levels() function: levels(yourdataframe$Position) This will list all of the factor levels in variable Position for you. If there are extras spaces and you were using read.csv() to import the data, use the strip.white=TRUE argument to delete leading and trailing spaces. This is also documented on the manual page for function read.csv()...
2008 Aug 24
1
Plotting 3 way Anova
Hi I'd really like to get a bar plot showing the means of my anova data. I have looked everywhere and can only seem to find instructions for 2 way anova's. I basically want to look at the mean condition of my subjects spilt by age, sex and year (as a factor rather than a continuous variable, hence Anova and not Ancova). and want to show it firstly as a bar graph with standard error. I
2005 Dec 07
1
KMO sampling adequacy and SPSS -- partial solution
...cor(df)^2 cor.sumsq = (sum(cor.sq)-dim(cor.sq)[1])/2 library(corpcor) pcor.sq = cor2pcor(cor(df))^2 pcor.sumsq = (sum(pcor.sq)-dim(pcor.sq)[1])/2 kmo = sus.cor.ss/(sus.cor.ss+sus.pcor.ss) return(kmo) } Also, for those trying to reproduce the SPSS factor analysis output, (-1 * cor2pcor(cor(yourDataFrame))) will produce the "anti-image correlation" matrix. Unfortunately, the most useful property of that matrix in SPSS is that the diagonals represent the individual MSA values -- I haven't found a way to derive those yet. Still working on that, any suggestions appreciated. --A...
2003 Dec 11
1
plot of survival probability vs. covariate
Hi everyone, I am fitting a cox proportional hazard model with a continuous variable "x" as the covariate: fit<-coxph(Surv(time, status)~x) Now I wanted to make a plot of survival probability vs. the covariate, and the 95% confidence interval for the survival probability. It's just like a Kaplan-Meier Survival curve, except now the x axis represents the value of covariate, not
2007 Oct 24
3
how to loop over a group of variables?
Hi All, I have a data frame with a group of variables named b1, b2, b3, ..., b18. These variables take the value 1, 2 or NA. For each observation, I want to do some computation by looping over the values for the group of variables: b1 to b18. In STATA I would do: forval i=1/18 { --- use b`i' for computation ---- } How can this be done in R? Deepankar
2007 Oct 25
2
the difference between temp and .temp
...What would be the advantages to doing so? Thanks in advance for what will surely be a collection of illuminating responses. tim On 10/25/07, jim holtman <jholtman at gmail.com> wrote: > Actually I forgot you have a data frame. so use: > > for (i in 1:18){ > .temp <- yourDataFrame[[paste('b', i, sep='')]] > .... use .temp .... > } > > > On 10/24/07, DEEPANKAR BASU <basu.15 at osu.edu> wrote: > > Hi All, > > > > I have a data frame with a group of variables named b1, b2, b3, ..., b18. These variables take the value...
2012 Feb 13
3
Change dataframe-structure
Ein eingebundener Text mit undefiniertem Zeichensatz wurde abgetrennt. Name: nicht verf?gbar URL: <https://stat.ethz.ch/pipermail/r-help/attachments/20120213/d2a5afa6/attachment.pl>
2010 Sep 17
2
grouping dataframe entries using a categorical variable
DearR Users, I have a problem which I think you might be able to help. I have a dataframe which I'm trying to "filter" following different groups I specified. It's a little hard to explain, so here is an example: My dataframe: ESS DHP 1 EPB 22 2 SAB 10 3 SAB 20 4 BOJ 14 5 ERS 28 11 SAB 10 12 SAB 22 13 BOJ 26 20 SAB 10 21 SAB 22 22 BOJ 32 29 SAB 14 30 SAB
2010 Dec 09
4
lapply getting names of the list
Hello All, I have a toy dataframe like this. It has 8 columns separated by tab. Name SampleID Al1 Al2 X Y R Th rs191191 A1 A B 0.999 0.09 0.78 0.090 abc928291 A1 B J 0.3838 0.3839 0.028 0.888 abcnab A1 H K 0.3939 0.939 0.3939 0.77 rx82922 B1 J K 0.3838 0.393
2012 Jul 03
2
NADA Data Frame Format: Wide or Long?
I have water chemistry data with censored values (i.e., those less than reporting levels) in a data frame with a narrow (i.e., database table) format. The structure is: $ site : Factor w/ 64 levels "D-1","D-2","D-3",..: 1 1 1 1 1 1 1 1 ... $ sampdate: Date, format: "2007-12-12" "2007-12-12" ... $ preeq0 : logi TRUE TRUE TRUE TRUE TRUE
2016 Apr 21
1
plot 8 functions on one graph?
I'm trying to use ggplot to make a single graph that plots 8 distributions, one above the other. I created a data.frame with 9 rows. The first is the coordinate along the x-axis. The next is the y-values for the first distribution. After that is the y-values for the next distribution... and so on. How do I call ggplot to use such a data.frame to make a single graph of 8 distributions?