R help - Apr 2006 - do.call method within namespace

How does one go about invoking a method within a namespaced
package if that package has not been loaded via library
method?

Given "mypackage" and method "foo" within:
    mypackage::foo(1, 2, 3)

Executing the same method's function call:
    do.call("foo", list(1, 2, 3))

didn't work. Nor did the following:
    do.call("mypackage::foo", list(1, 2, 3))

There some other means to do this without loading the
package via library method?

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SIGSIG -- signature too long (core dumped)

Paul Roebuck wrote:
> How does one go about invoking a method within a namespaced
> package if that package has not been loaded via library
> method?
> 
> Given "mypackage" and method "foo" within:
>     mypackage::foo(1, 2, 3)
> 
> Executing the same method's function call:
>     do.call("foo", list(1, 2, 3))
> 
> didn't work. Nor did the following:
>     do.call("mypackage::foo", list(1, 2, 3))
> 
> There some other means to do this without loading the
> package via library method?


do.call(getFromNamespace("foo", "mypackage"), list(1, 2, 3))

   where "mypackage" is a namespace...


Uwe Ligges


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