Adaikalavan Ramasamy wrote:> I am doing some coxPH model fitting and would like to have some idea
> about how good the fits are. Someone suggested to use Frank Harrell's
> C-index measure.
>
> As I understand it, a C-index > 0.5 indicates a useful model. I am
No, that just means predictions are better than random.
> probably making an error here because I am getting values less than 0.5
> on real datasets. Can someone tell me where I am going wrong please ?
>
> Here is an example using the German Breast Study Group data available in
> the mfp package. The predictors in the model were selected by stepAIC().
>
>
> library(Design); library(Hmisc); library(mfp); data(GBSG)
> fit <- cph( Surv( rfst, cens ) ~ htreat + tumsize + tumgrad +
> posnodal + prm, data=GBSG, x=T, y=T )
>
> val <- validate.cph( fit, dxy=T, B=200 )
> round(val, 3)
> index.orig training test optimism index.corrected n
> Dxy -0.377 -0.383 -0.370 -0.013 -0.364 200
> R2 0.140 0.148 0.132 0.016 0.124 200
> Slope 1.000 1.000 0.925 0.075 0.925 200
> D 0.028 0.030 0.027 0.004 0.025 200
> U -0.001 -0.001 0.002 -0.002 0.002 200
> Q 0.029 0.031 0.025 0.006 0.023 200
>
> 1) Am I correct in assuming C-index = 0.5 * ( Dxy + 1 ) ?
Yes
>
> 2) If so, I am getting 0.5*(-0.3634+1) = 0.318 for the C-index. Does
> this make sense ?
For the Cox model, the default calculation correlates the linear
predictor with survival time. A large linear predictor (large log
hazard) means shorter survival time. To phrase it in the more usually
way, negate Dxy before computing C.
Frank
>
> 3) Should I be using some other measurement instead of C-index.
>
> Thank you very much in advance.
>
> Regards, Adai
>
> ______________________________________________
> R-help at stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide!
http://www.R-project.org/posting-guide.html
>
--
Frank E Harrell Jr Professor and Chair School of Medicine
Department of Biostatistics Vanderbilt University