This works in R 1.7.1: please upgrade.
[That's assuming that your sequence actually covers the data: you need to
go beyond max(cas.param) to be sure, and it looks to me that with
right=FALSE and include.lowest-FALSE the breaks never will cover the
data.]
On Tue, 17 Jun 2003, Petr Pikal wrote:
> Dear all
>
> I would like to aggregate a data frame in a three minute interval. I have a
time
> vector:
>
> > str(cas.param)
> `POSIXct', format: chr [1:181] "2003-06-12 09:00:00"
"2003-06-12 09:01:00"
> "2003-06-12 09:02:00"
>
> and I want to turn it into a factor by cut. It works if I want to break it
in let say
> hours
>
> > str(cut(cas.param,breaks="hour"))
> Factor w/ 3 levels "2003-06-12 ..",..: 1 1 1 1 1 1 1 1 1 1 .
>
> But if i tried to do similar task but to construct three minutes intervals
with a
> vector of cut points it gives me an error
>
> > cut(cas.param,breaks=seq(min(cas.param),max(cas.param), by="3
mins"))
> Error in sort(breaks) : `x' must be atomic
>
> however
>
> > str(seq(min(cas.param),max(cas.param), by="3 mins"))
> `POSIXct', format: chr [1:61] "2003-06-12 09:00:00"
"2003-06-12 09:03:00"
> "2003-06-12 09:06:00"
>
> works.
>
> So it is definitely my lack of understanding how to implement a vector of
cut
> points (constructed by seq()), to break parameter of cut() function.
>
> Please can you give me any hints?
>
> R 1.7.0, Windows NT
>
> Thanks a lot
>
> Petr Pikal
> petr.pikal at precheza.cz
> p.pik at volny.cz
>
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> R-help at stat.math.ethz.ch mailing list
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>
--
Brian D. Ripley, ripley at stats.ox.ac.uk
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
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