Dan Langille via Nut-upsuser <nut-upsuser at alioth-lists.debian.net> writes:>> On the website, they say 5.73 pounds (5 lbs 11.6 oz). >> >> Two of the batteries were 5 lbs 11 oz. The rest were all 10, 9, or 8 oz. >> >> See my bar chart at https://bsd.network/web/@dvl/113555334752647203 > > The batteries are all within 3% of the expected weight. Seems good enough for me. > > I gave some thought as to how to distribute those 16x batteries within the UPS (4x) and the external battery unit (12x). > > In the following, I'm omitting the 5lb part of the weight and mention only the ounces. > > Not that I think it will make much difference, but I'll put all the four equal batteries into the UPS (4x 10oz batteries). > > That will leave the following for the external pack: > ' > * 2 x 11 > * 1 x 10 > * 7 x 9 > * 2 x 8 > > The other choice I'd make: put 2 x 11 and 2 x 10 in the UPS, leaving the external battery > unit with: > > * 3 x 10 > * 7 x 9 > * 2 x 8 > > I don't know enough to know if this matters and I expect I'm merely overthinking this.You are definitely overthinking it :-) Perhaps you've previously been diagnosed as a nerd! But, I would either put the 4 strongest in the UPS, or the 4 weakest, making the external pack better, since it is more important. I would suggest that you get a West Mountain CBA, if you want to continue to overthink this. We are assuming that more lead is more capacity, but there are also weak cells, not clearly related to missing lead. What really matters, IMHO, is how many Ah one can pull out of the battery, and measuring that directly seems more direct. There's also the question of discharge rate. I used to use standard rates of 1 A, larger for bigger bateries, smaller for little ones. This is contrary to industry norm which is a 20h rate. Then I had batteries I wanted to return, and realized I really needed to test at the specified rate. So now i do 20h rate, which which means nameplate capacity / 20h, so 450 mA for a battery specified at 9 Ah. With end-of-test at 10.5V, which you'll find on the spec sheet. Of course, the actual time will not be 20h, and one could attempt to find the rate which leads to 20h, but I don't think that's a sensible thing to do. Basically, if I get > 8.5Ah when discharging a 9Ah at 450 mA, I call it good. And > 8 Ah I call it ok, sort of they are making an 8 Ah battery and the marketing people call it 9. I will probably be getting some new batteries over the next few months and will test them on intake, and weigh them too. Thanks for posting about your journey; it has been illuminating to me.
On Wed, Nov 27, 2024, at 10:56 AM, Greg Troxel via Nut-upsuser wrote:> Dan Langille via Nut-upsuser <nut-upsuser at alioth-lists.debian.net> > writes: > >>> On the website, they say 5.73 pounds (5 lbs 11.6 oz). >>> >>> Two of the batteries were 5 lbs 11 oz. The rest were all 10, 9, or 8 oz. >>> >>> See my bar chart at https://bsd.network/web/@dvl/113555334752647203 >> >> The batteries are all within 3% of the expected weight. Seems good enough for me. >> >> I gave some thought as to how to distribute those 16x batteries within the UPS (4x) and the external battery unit (12x). >> >> In the following, I'm omitting the 5lb part of the weight and mention only the ounces. >> >> Not that I think it will make much difference, but I'll put all the four equal batteries into the UPS (4x 10oz batteries). >> >> That will leave the following for the external pack: >> ' >> * 2 x 11 >> * 1 x 10 >> * 7 x 9 >> * 2 x 8 >> >> The other choice I'd make: put 2 x 11 and 2 x 10 in the UPS, leaving the external battery >> unit with: >> >> * 3 x 10 >> * 7 x 9 >> * 2 x 8 >> >> I don't know enough to know if this matters and I expect I'm merely overthinking this. > > You are definitely overthinking it :-) Perhaps you've previously been > diagnosed as a nerd!Possibly. I also have a rain-barrel project underway, and I know I'm overthinking that one too.> But, I would either put the 4 strongest in the UPS, or the 4 weakest, > making the external pack better, since it is more important. > > I would suggest that you get a West Mountain CBA, if you want to > continue to overthink this. We are assuming that more lead is more > capacity, but there are also weak cells, not clearly related to missing > lead. What really matters, IMHO, is how many Ah one can pull out of > the battery, and measuring that directly seems more direct.I understand, and no, I'm done with this stage of the process. I don't want to geek out any further. So far, every battery has been charged. Each took about 30 minutes. When charged they measured about 13.3-13.5V. The first batteries I charged are now at about 12.9-13.1V - one was 12.8V They're sitting in a room that is about 63F. My next step is to pull the main battery from the 5PX and replace those units. However, it's 3:30 PM and I'd rather start such a project earlier in the day should thing take longer than expected. One server has a drive ready to be replaced and two drives are to be relocated from the drive bays at the front to PCI slots in the rear of the server. That process is waiting on parts. I was going to wait for those parts and do the drives and batteries at the same time. I changed my mind; I'm not going to wait. Plus, the batteries may be a big enough job by themselves. I am sure the Eaton 5PX legacy is not a hot-swappable unit. I'll power everything down.> Thanks for posting about your journey; it has been illuminating to me.I'm glad it helps. I write mostly for selfish reasons and encourage others to do so too. It helps to know what you did should something go wrong and/or you want to repeat the procedure later. If you make your writing public it will also help others and I'm thankful of that. -- Dan Langille dan at langille.org