Hello, I'm trying to convert a character column in several dataframes to lower case. ### # # Sample data and 'spp' column summaries: # dput(ban.ovs.1993[sample(row.names(ban.ovs.1993), 20), 1:4]) ban.ovs.93 <- structure(list(oplt = c(43L, 43L, 38L, 26L, 35L, 8L, 39L, 1L, 34L, 50L, 10L, 29L, 31L, 24L, 18L, 12L, 27L, 49L, 28L, 51L), rplt = c(NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_), tree = c(427L, 410L, 639L, 494L, 649L, 166L, 735L, 163L, 120L, 755L, 612L, 174L, 129L, 331L, 269L, 152L, 552L, 227L, 243L, 96L), spp = c("MH", "MST", "MH", "HE", "BE", "MH", "MH", "MH", "MH", "Or", "IW", "Or", "MH", "MH", "BY", "MH", "MH", "BE", "MH", "MR")), .Names = c("oplt", "rplt", "tree", "spp"), row.names = c(4587L, 4570L, 3947L, 2761L, 3653L, 652L, 4136L, 64L, 3567L, 5318L, 838L, 3091L, 3366L, 2423L, 1775L, 1061L, 2893L, 5161L, 2967L, 5395L), class = "data.frame") # dput(pem.ovs.1994[sample(row.names(pem.ovs.1994), 20), 1:4]) pem.ovs.94 <- structure(list(oplt = c(8L, 17L, 36L, 9L, 31L, 11L, 35L, 51L, 51L, 49L, 40L, 1L, 9L, 17L, 4L, 42L, 6L, 3L, 39L, 25L), tree = c(531L, 557L, 546L, 261L, 592L, 134L, 695L, 933L, 945L, 114L, 34L, 54L, 549L, 574L, 193L, 96L, 70L, 4L, 546L, 789L), spp = c("MH", "MH", "MH", "BF", "BF", "MH", "IW", "OR", "OR", "BF", "MH", "IW", "OR", "MH", "SM", "BE", "BE", "BE", "OR", "OR"), oaz = c(38L, 205L, 140L, 277L, 329L, 209L, 222L, 24L, 67L, 187L, 156L, 181L, 174L, 248L, 42L, 279L, 273L, 357L, 160L, 183L)), .Names = c("oplt", "tree", "spp", "oaz"), row.names = c(1204L, 2943L, 5790L, 1616L, 5063L, 2013L, 5691L, 8188L, 8200L, 7822L, 6302L, 54L, 1698L, 2960L, 421L, 6690L, 775L, 245L, 6205L, 4121L), class = "data.frame") # count per spp invisible(lapply(ls(pat='ovs'), function(y) { cat(y, "\n") ; print(summary.factor(get(y)[,'spp'])) ; cat("\n") } ) ) ban.ovs.93 BE BY HE IW MH MR MST Or 2 1 1 1 11 1 1 2 pem.ovs.94 BE BF IW MH OR SM 3 3 2 6 5 1 # ### I have tried variants on the following and cannot remember how to have the result assign()ed back to the original dataframes. lapply(ls(pat='ovs'), function(y) { assign(paste(y, "[,'spp']", sep=""), tolower(get(y)[,'spp'])) } ) I *do* get the expected results: [[1]] [1] "mh" "mst" "mh" "he" "be" "mh" "mh" "mh" "mh" "or" "iw" "or" "mh" "mh" "by" "mh" "mh" "be" "mh" "mr" [[2]] [1] "mh" "mh" "mh" "bf" "bf" "mh" "iw" "or" "or" "bf" "mh" "iw" "or" "mh" "sm" "be" "be" "be" "or" "or" , I just can't remember how to get them back into the original dataframe objects. Suggestions? Thanx, DaveT. ************************************* Silviculture Data Analyst Ontario Forest Research Institute Ontario Ministry of Natural Resources david.john.thompson at ontario.ca http://ontario.ca/ofri
Any tips? DaveT.>-----Original Message----- >From: Thompson, David (MNR) >Sent: December 9, 2008 04:03 PM >To: 'r-help at r-project.org' >Subject: assign()ing within apply > >Hello, > >I'm trying to convert a character column in several dataframes >to lower case. > >### ># ># Sample data and 'spp' column summaries: ># dput(ban.ovs.1993[sample(row.names(ban.ovs.1993), 20), 1:4]) >ban.ovs.93 <- structure(list(oplt = c(43L, 43L, 38L, 26L, 35L, >8L, 39L, 1L, >34L, 50L, 10L, 29L, 31L, 24L, 18L, 12L, 27L, 49L, 28L, 51L), > rplt = c(NA_integer_, NA_integer_, NA_integer_, NA_integer_, > NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, > NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, > NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, > NA_integer_), tree = c(427L, 410L, 639L, 494L, 649L, 166L, > 735L, 163L, 120L, 755L, 612L, 174L, 129L, 331L, 269L, 152L, > 552L, 227L, 243L, 96L), spp = c("MH", "MST", "MH", "HE", > "BE", "MH", "MH", "MH", "MH", "Or", "IW", "Or", "MH", "MH", > "BY", "MH", "MH", "BE", "MH", "MR")), .Names = c("oplt", >"rplt", "tree", "spp"), row.names = c(4587L, 4570L, 3947L, 2761L, >3653L, 652L, 4136L, 64L, 3567L, 5318L, 838L, 3091L, 3366L, 2423L, >1775L, 1061L, 2893L, 5161L, 2967L, 5395L), class = "data.frame") > ># dput(pem.ovs.1994[sample(row.names(pem.ovs.1994), 20), 1:4]) >pem.ovs.94 <- structure(list(oplt = c(8L, 17L, 36L, 9L, 31L, >11L, 35L, 51L, >51L, 49L, 40L, 1L, 9L, 17L, 4L, 42L, 6L, 3L, 39L, 25L), tree = c(531L, >557L, 546L, 261L, 592L, 134L, 695L, 933L, 945L, 114L, 34L, 54L, >549L, 574L, 193L, 96L, 70L, 4L, 546L, 789L), spp = c("MH", "MH", >"MH", "BF", "BF", "MH", "IW", "OR", "OR", "BF", "MH", "IW", "OR", >"MH", "SM", "BE", "BE", "BE", "OR", "OR"), oaz = c(38L, 205L, >140L, 277L, 329L, 209L, 222L, 24L, 67L, 187L, 156L, 181L, 174L, >248L, 42L, 279L, 273L, 357L, 160L, 183L)), .Names = c("oplt", >"tree", "spp", "oaz"), row.names = c(1204L, 2943L, 5790L, 1616L, >5063L, 2013L, 5691L, 8188L, 8200L, 7822L, 6302L, 54L, 1698L, >2960L, 421L, 6690L, 775L, 245L, 6205L, 4121L), class = "data.frame") > ># count per spp >invisible(lapply(ls(pat='ovs'), function(y) { cat(y, "\n") ; >print(summary.factor(get(y)[,'spp'])) ; cat("\n") } ) ) >ban.ovs.93 >BE BY HE IW MH MR MST Or > 2 1 1 1 11 1 1 2 > >pem.ovs.94 >BE BF IW MH OR SM > 3 3 2 6 5 1 ># >### > >I have tried variants on the following and cannot remember how >to have the result assign()ed back to the original dataframes. >lapply(ls(pat='ovs'), function(y) { assign(paste(y, >"[,'spp']", sep=""), tolower(get(y)[,'spp'])) } ) > >I *do* get the expected results: >[[1]] > [1] "mh" "mst" "mh" "he" "be" "mh" "mh" "mh" "mh" >"or" "iw" "or" "mh" "mh" "by" "mh" "mh" "be" "mh" "mr" > >[[2]] > [1] "mh" "mh" "mh" "bf" "bf" "mh" "iw" "or" "or" "bf" "mh" >"iw" "or" "mh" "sm" "be" "be" "be" "or" "or" > >, I just can't remember how to get them back into the original >dataframe objects. Suggestions? > >Thanx, DaveT. >************************************* >Silviculture Data Analyst >Ontario Forest Research Institute >Ontario Ministry of Natural Resources >david.john.thompson at ontario.ca >http://ontario.ca/ofri >*************************************
Thanks Jorge, I am aware of the method you suggest, however, it's not quite what I was asking for. I was attempting to do this change on 56 dataframes, so I attempted to do so with a list of all rather than each individually. Thanks, DaveT. ________________________________ From: Jorge Ivan Velez [mailto:jorgeivanvelez@gmail.com] Sent: December 12, 2008 11:11 AM To: Thompson, David (MNR) Subject: Re: [R] assign()ing within apply Dear David, Try this: ban.ovs.93[,'spp']<-tolower(ban.ovs.93[,'spp']) ban.ovs.93 pem.ovs.94[,'spp']<-tolower(pem.ovs.94[,'spp']) pem.ovs.94 HTH, Jorge On Fri, Dec 12, 2008 at 9:51 AM, Thompson, David (MNR) <David.John.Thompson@ontario.ca> wrote: Any tips? DaveT. >-----Original Message----- >From: Thompson, David (MNR) >Sent: December 9, 2008 04:03 PM >To: 'r-help@r-project.org' >Subject: assign()ing within apply > >Hello, > >I'm trying to convert a character column in several dataframes >to lower case. > >### ># ># Sample data and 'spp' column summaries: ># dput(ban.ovs.1993[sample(row.names(ban.ovs.1993), 20), 1:4]) >ban.ovs.93 <- structure(list(oplt = c(43L, 43L, 38L, 26L, 35L, >8L, 39L, 1L, >34L, 50L, 10L, 29L, 31L, 24L, 18L, 12L, 27L, 49L, 28L, 51L), > rplt = c(NA_integer_, NA_integer_, NA_integer_, NA_integer_, > NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, > NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, > NA_integer_, NA_integer_, NA_integer_, NA_integer_, NA_integer_, > NA_integer_), tree = c(427L, 410L, 639L, 494L, 649L, 166L, > 735L, 163L, 120L, 755L, 612L, 174L, 129L, 331L, 269L, 152L, > 552L, 227L, 243L, 96L), spp = c("MH", "MST", "MH", "HE", > "BE", "MH", "MH", "MH", "MH", "Or", "IW", "Or", "MH", "MH", > "BY", "MH", "MH", "BE", "MH", "MR")), .Names c("oplt", >"rplt", "tree", "spp"), row.names = c(4587L, 4570L, 3947L, 2761L, >3653L, 652L, 4136L, 64L, 3567L, 5318L, 838L, 3091L, 3366L, 2423L, >1775L, 1061L, 2893L, 5161L, 2967L, 5395L), class "data.frame") > ># dput(pem.ovs.1994[sample(row.names(pem.ovs.1994), 20), 1:4]) >pem.ovs.94 <- structure(list(oplt = c(8L, 17L, 36L, 9L, 31L, >11L, 35L, 51L, >51L, 49L, 40L, 1L, 9L, 17L, 4L, 42L, 6L, 3L, 39L, 25L), tree = c(531L, >557L, 546L, 261L, 592L, 134L, 695L, 933L, 945L, 114L, 34L, 54L, >549L, 574L, 193L, 96L, 70L, 4L, 546L, 789L), spp c("MH", "MH", >"MH", "BF", "BF", "MH", "IW", "OR", "OR", "BF", "MH", "IW", "OR", >"MH", "SM", "BE", "BE", "BE", "OR", "OR"), oaz = c(38L, 205L, >140L, 277L, 329L, 209L, 222L, 24L, 67L, 187L, 156L, 181L, 174L, >248L, 42L, 279L, 273L, 357L, 160L, 183L)), .Names c("oplt", >"tree", "spp", "oaz"), row.names = c(1204L, 2943L, 5790L, 1616L, >5063L, 2013L, 5691L, 8188L, 8200L, 7822L, 6302L, 54L, 1698L, >2960L, 421L, 6690L, 775L, 245L, 6205L, 4121L), class "data.frame") > ># count per spp >invisible(lapply(ls(pat='ovs'), function(y) { cat(y, "\n") ; >print(summary.factor(get(y)[,'spp'])) ; cat("\n") } ) ) >ban.ovs.93 >BE BY HE IW MH MR MST Or > 2 1 1 1 11 1 1 2 > >pem.ovs.94 >BE BF IW MH OR SM > 3 3 2 6 5 1 ># >### > >I have tried variants on the following and cannot remember how >to have the result assign()ed back to the original dataframes. >lapply(ls(pat='ovs'), function(y) { assign(paste(y, >"[,'spp']", sep=""), tolower(get(y)[,'spp'])) } ) > >I *do* get the expected results: >[[1]] > [1] "mh" "mst" "mh" "he" "be" "mh" "mh" "mh" "mh" >"or" "iw" "or" "mh" "mh" "by" "mh" "mh" "be" "mh" "mr" > >[[2]] > [1] "mh" "mh" "mh" "bf" "bf" "mh" "iw" "or" "or" "bf" "mh" >"iw" "or" "mh" "sm" "be" "be" "be" "or" "or" > >, I just can't remember how to get them back into the original >dataframe objects. Suggestions? > >Thanx, DaveT. >************************************* >Silviculture Data Analyst >Ontario Forest Research Institute >Ontario Ministry of Natural Resources >david.john.thompson@ontario.ca >http://ontario.ca/ofri >************************************* ______________________________________________ R-help@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code. [[alternative HTML version deleted]]