similar to: assign()ing within apply

Hello, I have a set of one-liners (many thanks to previous responses from this list) that I use to look at newly imported data sets with functions like dim(), names(), str(), etc. within lapply(). Generally, these commands work for me but, I am apparently still missing some aspect of list manipulation. I don't understand why I get a set of NULL list elements at the end of each output as

Hello, I am unable to figure out how to code a new column in a data frame based on an existing column that matches a column in a reference data frame, in a relational-db fashion. I would like this to maintain a minimum set of reference tables that may be reused over several similar datasets. Specifically, I have two data frames as listed below, 'Bos' and 'tree.' For each case in

Hello, Two lapply questions (system info and sample data below): 1) Why does the first form of command1 add the name of y _after_ the str() output rather than before as does the second (preferred) form? # command1 version1 invisible(lapply(ls(pattern='bn'), function(y) cat(y, "\n", str(get(y)), "\n") )) # command1 version2 (preferred output)

Hello, A few questions about the following examples: 1. Why do the two plotting versions not produce the same result? 2. Is the 'scale_x_continuous' (or *_y_* or *_*_discrete) geom the best way to setup grids (as in visual guide-lines) in polar (or for that matter, any) coordinate system? 3. Why do these commands appear to generate 3 plot pages each? 4. Perhaps more questions to follow

Muchas gracias, pero claro en una muestra de 50 datos se ejecuta, en la muestra original de 1000 registros me tira error :( 2013/10/30 daniel <daniel319@gmail.com> > Amalia, > > No obtengo tus resultados. Corrí tus formulas y datos y el resultado es > x <- structure(list(ï..psraid = c(202517L, 202518L, 202520L, 202523L, > + 202527L, 202537L, 202543L, 202544L, 202551L,

Saludo gente, antes que nada gracias por la ayuda que puedan aportarme, soy iniciante en R, estoy usando el paquete Mice para realizar imputaciones múltiples sobre variables en su mayoría categóricas. El problema está que cuando expresó este comando imp <- mice(dataset,method="polr",maxit=1) donde el dataset es un data.frame me tirá este error : iter imp variable 1 1 pial1a

Hi I'm trying to extract complete rows from a dataframe by group based on the maximum in a column within that group. Thus I have a dataframe: cvd_basestudy ... es_time ... _____________ study1 ... 0.3091667 study2 ... 0.3091667 study2 ... 0.2625000 study3 ... 0.3033333 study3 ... 0.2625000 __________ etc I can extract the basestudy and the max(es_time)

I am trying to set up a data set for a survival analysis with time-varying covariates. The data is already in a long format, but does not have a variable to signify the stopping point for the interval. The variable DaysEnrolled is the variable I would like to use to form this interval. This is what I have now: ID Age DaysEnrolled HAZ WAZ WHZ Food onARV

I'm trying to populate the column ?pf_mcl? in myDF1 with values from myDF2, where rows match based on column "studyno" but the solutions I have found so far don't seem to be giving me the desired output. Below is a snapshot of the data.frames. myDF1 <- structure(list(studyno = c("J1000/9", "J1000/9", "J1000/9", "J1000/9",

Hello, Try the following. myDF1$studyno <- as.character(myDF1$studyno) myDF2$studyno <- as.character(myDF2$studyno) i1 <- which(names(myDF1) == "pf_mcl") merge(myDF1[-i1], myDF2, by = "studyno") Hope this helps, Rui Barradas Em 13-10-2017 20:09, Kevin Wamae escreveu: > I'm trying to populate the column ?pf_mcl? in myDF1 with values from myDF2, where rows

?merge Bert On Oct 13, 2017 12:09 PM, "Kevin Wamae" <KWamae at kemri-wellcome.org> wrote: > I'm trying to populate the column ?pf_mcl? in myDF1 with values from > myDF2, where rows match based on column "studyno" but the solutions I have > found so far don't seem to be giving me the desired output. > > Below is a snapshot of the data.frames. >

Your example used one distinct studyno in DF1 and one distinct pf_mcl in DF2. I think that makes it hard to see what is going on, but maybe I completely misunderstand the problem. In any case, let's redefine myDF1 and myDF2. Note that myDF1 contains a studyno not in myDF2 and vice versa. myDF1 <- structure(list(studyno = c("J1000/9", "J895/7", "J931/6",

Dear @Bert Gunter<mailto:bgunter.4567 at gmail.com>, I tried merge and I faced many challenges. @Rui Barradas<mailto:ruipbarradas at sapo.pt> solution is working. From: Bert Gunter <bgunter.4567 at gmail.com> Date: Friday, 13 October 2017 at 22:44 To: Kevin Wamae <KWamae at kemri-wellcome.org> Cc: R-help <R-help at r-project.org> Subject: Re: [R] Populate one data

>>>>> Martin Maechler >>>>> on Fri, 11 Jan 2019 09:44:14 +0100 writes: >>>>> Michael Chirico >>>>> on Fri, 11 Jan 2019 14:36:17 +0800 writes: >> Identified as root cause of a bug in data.table: >> https://github.com/Rdatatable/data.table/issues/3267 >> On my machine, strtoi("", base =

Dear @Rui Barradas, thank you for the solution. It works perfectly. On 13/10/2017, 23:35, "Rui Barradas" <ruipbarradas at sapo.pt> wrote: Hello, Try the following. myDF1$studyno <- as.character(myDF1$studyno) myDF2$studyno <- as.character(myDF2$studyno) i1 <- which(names(myDF1) == "pf_mcl") merge(myDF1[-i1], myDF2,

Dear @William<mailto:wdunlap at tibco.com>, thanks for the feedback. I have tested it on the larger dataset and noticed that it created two variables, pf_raw and pf_curated. The output we were looking for, was one that takes the variable pf_mcl in curated dataset and replaces pf_mcl in matching rows within the raw dataset. @Eric<mailto:ericjberger at gmail.com>?s solution was able to

Identified as root cause of a bug in data.table: https://github.com/Rdatatable/data.table/issues/3267 On my machine, strtoi("", base = 2L) produces NA_integer_ (which seems consistent with ?strtoi: "Values which cannot be interpreted as integers or would overflow are returned as NA_integer_"). But on all the other machines I've seen, 0L is returned. This seems to be

Hi Kevin, I think there are issues with Rui's proposed solution. For example, if there are rows in myDF1 which have a studyno which does not match any row in myDF2, then you will lose those rows. In your original request you said that you wanted to keep those rows. To demonstrate my point I need to modify your sample data. Specifically, I changed some studyno settings in myDF1, and also the

Hi all, Surprisingly (at least to me), `as.complex(NA_real_)` results in `complex(real = NA_real_, imaginary = 0)` rather than `NA_complex_`. It seems to me that this goes against the docs of `as.complex()`, which say this in the Details section: "Up to R versions 3.2.x, all forms of NA and NaN were coerced to a complex NA, i.e., the NA_complex_ constant, for which both the real and

Hello, using the `unsplit()` function with tibbles currently leads to the following error: > mtcars_tb <- as_tibble(mtcars, rownames = NULL) > s <- split(mtcars_tb, mtcars_tb$gear) > unsplit(s, mtcars_tb$gear) Error: Must subset rows with a valid subscript vector. ? Logical subscripts must match the size of the indexed input. x Input has size 15 but subscript `rep(NA, len)` has