R help - Jun 2008 - selecting values that are unique, instead of selecting unique values

unique(c(1:10,1)) gives 1:10 (i.e. unique values), is there any method to get
only 2:10 (i.e. values that are unique) ?
 
 
 
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on 06/25/2008 11:19 AM Daren Tan wrote:
> 
> unique(c(1:10,1)) gives 1:10 (i.e. unique values), is there any
> method to get only 2:10 (i.e. values that are unique) ?
> 
The easiest might be:

 > Vec
  [1]  1  2  3  4  5  6  7  8  9 10  1

 > Vec[table(Vec) == 1]
[1]  2  3  4  5  6  7  8  9 10

HTH,

Marc Schwartz

Hmmm, this is not very good:
> Vec <- c(10:1,1)
> Vec[ table(Vec) == 1 ]
[1] 9 8 7 6 5 4 3 2 1

and these are obviously not the unique values.....
This one is better:

Vec [ ! duplicated(Vec) & ! duplicated(Vec, fromLast=TRUE) ]

Gabor

On Wed, Jun 25, 2008 at 11:29:31AM -0500, Marc Schwartz
wrote:
> on 06/25/2008 11:19 AM Daren Tan wrote:
>>
>> unique(c(1:10,1)) gives 1:10 (i.e. unique values), is there any
>> method to get only 2:10 (i.e. values that are unique) ?
>>
>
> The easiest might be:
>
> > Vec
>  [1]  1  2  3  4  5  6  7  8  9 10  1
>
> > Vec[table(Vec) == 1]
> [1]  2  3  4  5  6  7  8  9 10
>
> HTH,
>
> Marc Schwartz
>
> ______________________________________________
> R-help at r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
-- 
Csardi Gabor <csardi at rmki.kfki.hu>    UNIL DGM

On Wed, Jun 25, 2008 at 12:19 PM, Daren Tan <daren76 at hotmail.com>
wrote:
>
>
> unique(c(1:10,1)) gives 1:10 (i.e. unique values), is there any method to
get only 2:10 (i.e. values that are unique) ?
>
>
Try this:

setdiff(x, x[duplicated(x)])