If 'oxygen' is a matrix with one row or column, 'oxygen' is
treated as
a one-dimensional contingency table. In this case, the hypothesis
tested is whether the population probabilities equal those in 'p', or
are all equal if 'p' is not given.
you can convert the 'oxygen' and 'train' variables to vector or
take a
two-dimensional contingency table by matrix(c(oxygen, train), nr=2).
you will get more information when you type ?chisq.test.
2005/5/27, Brett Stansfield <brett at
hbrc.govt.nz>:>
> Dear R help
> I have been trying to conduct a chi square test on two groups of variables
> to test whether there is any relationship between the two sets of variables
>
> chisq.test(oxygen, train)
>
> Pearson's Chi-squared test
>
> data: oxygen
> X-squared = 26.6576, df = 128, p-value = 1
>
> > chisq.test(oxygen)
>
> Pearson's Chi-squared test
>
> data: oxygen
> X-squared = 26.6576, df = 128, p-value = 1
>
> It looks as if R is only reading the first set of variables pertaining to
> oxygen. Is there a way for it to test for two groups of variables?
>
> brett stansfield
>
> Brett Stansfield
> Environmental Scientist - Water Quality
> Hawke's Bay Regional Council
> 102 Vautier Street
> Private Bag 6006
> Napier
> Phone (06) 835-9200 extn 9334
> Fax (06) 835-3601
>
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