Hi,
Try this:
dat1<-read.table(text="
?????? id??? date??????? a??????? b????? c??????? y
1????? 1 8/6/2008??? Red??? 15??? B????????? 22
2????? 1 8/6/2008? Green? 15??? B????????? 22
",sep="",header=TRUE)
?dat1$date<-with(dat1,as.factor(date))
?dat1
? id???? date???? a? b c? y
1? 1 8/6/2008?? Red 15 B 22
2? 1 8/6/2008 Green 15 B 22
?is.factor(dat1$date)
[1] TRUE
A.K.
----- Original Message -----
From: Yolande Tra <yolande.tra at gmail.com>
To: r-help at r-project.org
Cc:
Sent: Friday, July 20, 2012 10:44 AM
Subject: [R] convert date to a factor
Hello,
I would like to convert date as a factor to represent time in a repeated
measure situation in the following code. How would I do
that?>? d <- read.csv(file.path(dataDir,"data.csv"),
as.is=T,stringsAsFactors FALSE)
> d[1:2,]
? ? ? ? id? ? date? ? ? ? a? ? ? ? b? ? ? c? ? ? ? y
1? ? ? 1 8/6/2008? ? Red? ? 15? ? B? ? ? ? ? 22
2? ? ? 1 8/6/2008? Green? 15? ? B? ? ? ? ? 22
Thank you,
Y
??? [[alternative HTML version deleted]]
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