Hi,
You can do that even without apply():
v.v<-seq(10,20, by=0.1)
y<-v.v^2
But if you want it with apply...
apply(as.matrix(v.v), 1, function(x) x^2)
Regards,
Carlos Ortega
www.qualityexcellence.es
2012/1/31 arunkumar1111 <akpbond007@gmail.com>
> Hi
>
> I have a function
>
> y= x^2
>
> min =10
> max=20
> increment=0.1
>
> I want to find the value of y for the value of x between min and max by
> step
> increment.
>
> how to get the values using apply function instead of for loop
>
> -----
> Thanks in Advance
> Arun
> --
> View this message in context:
>
http://r.789695.n4.nabble.com/Help-required-in-using-apply-instead-of-for-loop-tp4344350p4344350.html
> Sent from the R help mailing list archive at Nabble.com.
>
> ______________________________________________
> R-help@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
[[alternative HTML version deleted]]