Hi Christofer, You might try sapply(listObj, function(l) l[1:max(sapply(listObj, length))] ) HTH, Jorge On Wed, Apr 27, 2011 at 1:23 PM, Bogaso Christofer <> wrote:> Dear all, let say, I have following list object: > > > > listObj <- vector("list", length = 3) > > listObj[[1]] <- rnorm(3) > > listObj[[2]] <- rnorm(4) > > listObj[[3]] <- rnorm(5) > > > > Now I want to convert above list into a Matrix. Ofcourse I can do it using > "Reduce("rbind", listObj)". However as you notice that as elements of that > list are arbitrary length vectors, I cant use this trick. What I want is to > have a matrix with 3x5 dimension, where the remaining element of each row > with be filled with NA, i.e I want : > > > > rbind(c(listObj[[1]], c(NA, NA)), c(listObj[[2]], c(NA)),listObj[[3]]) > > > > Is there any better way on how I can do that more directly? > > > > Thanks and regards, > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >[[alternative HTML version deleted]]
Here's one way:> uselen = max(sapply(listObj,length)) > do.call(rbind,lapply(listObj,function(x){length(x) = uselen;x}))[,1] [,2] [,3] [,4] [,5] [1,] 0.0702225 -1.143031 1.6437560 NA NA [2,] -0.6100869 2.657910 -0.6028418 -0.7739858 NA [3,] -2.5787357 1.381395 -1.6545857 0.8239982 -1.169961 - Phil Spector Statistical Computing Facility Department of Statistics UC Berkeley spector at stat.berkeley.edu On Wed, 27 Apr 2011, Bogaso Christofer wrote:> Dear all, let say, I have following list object: > > > > listObj <- vector("list", length = 3) > > listObj[[1]] <- rnorm(3) > > listObj[[2]] <- rnorm(4) > > listObj[[3]] <- rnorm(5) > > > > Now I want to convert above list into a Matrix. Ofcourse I can do it using > "Reduce("rbind", listObj)". However as you notice that as elements of that > list are arbitrary length vectors, I cant use this trick. What I want is to > have a matrix with 3x5 dimension, where the remaining element of each row > with be filled with NA, i.e I want : > > > > rbind(c(listObj[[1]], c(NA, NA)), c(listObj[[2]], c(NA)),listObj[[3]]) > > > > Is there any better way on how I can do that more directly? > > > > Thanks and regards, > > > [[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >
Dear all, let say, I have following list object:
listObj <- vector("list", length = 3)
listObj[[1]] <- rnorm(3)
listObj[[2]] <- rnorm(4)
listObj[[3]] <- rnorm(5)
Now I want to convert above list into a Matrix. Ofcourse I can do it using
"Reduce("rbind", listObj)". However as you notice that as
elements of that
list are arbitrary length vectors, I cant use this trick. What I want is to
have a matrix with 3x5 dimension, where the remaining element of each row
with be filled with NA, i.e I want :
rbind(c(listObj[[1]], c(NA, NA)), c(listObj[[2]], c(NA)),listObj[[3]])
Is there any better way on how I can do that more directly?
Thanks and regards,
[[alternative HTML version deleted]]
Try this: sapply(listObj, '[', 1:max(sapply(listObj, length))) On Wed, Apr 27, 2011 at 2:23 PM, Bogaso Christofer <bogaso.christofer at gmail.com> wrote:> Dear all, let say, I have following list object: > > > > listObj <- vector("list", length = 3) > > listObj[[1]] <- rnorm(3) > > listObj[[2]] <- rnorm(4) > > listObj[[3]] <- rnorm(5) > > > > Now I want to convert above list into a Matrix. Ofcourse I can do it using > "Reduce("rbind", listObj)". However as you notice that as elements of that > list are arbitrary length vectors, I cant use this trick. What I want is to > have a matrix with 3x5 dimension, where the remaining element of each row > with be filled with NA, i.e I want : > > > > rbind(c(listObj[[1]], c(NA, NA)), c(listObj[[2]], c(NA)),listObj[[3]]) > > > > Is there any better way on how I can do that more directly? > > > > Thanks and regards, > > > ? ? ? ?[[alternative HTML version deleted]] > > ______________________________________________ > R-help at r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >-- Henrique Dallazuanna Curitiba-Paran?-Brasil 25? 25' 40" S 49? 16' 22" O