Suppose that I have a list of vectors. I want to compute the union of all the vectors in the list. I could use 'for' loop to do so. But I'm wondering what would be a better solution that does not need a 'for' loop. l=list(a=c(1,3,4), b=c(1,3,6), c=c(1,3,7), ....)
Hi Peng, Here is a suggestion: unique(do.call(c, l)) # [1] 1 3 4 6 7 Best regards, Jorge On Wed, Oct 28, 2009 at 3:07 PM, Peng Yu <> wrote:> Suppose that I have a list of vectors. I want to compute the union of > all the vectors in the list. I could use 'for' loop to do so. But I'm > wondering what would be a better solution that does not need a 'for' > loop. > > l=list(a=c(1,3,4), b=c(1,3,6), c=c(1,3,7), ....) > > ______________________________________________ > R-help@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide > http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. >[[alternative HTML version deleted]]
Peng Yu wrote:> > Suppose that I have a list of vectors. I want to compute the union of > all the vectors in the list. I could use 'for' loop to do so. But I'm > wondering what would be a better solution that does not need a 'for' > loop. > > l=list(a=c(1,3,4), b=c(1,3,6), c=c(1,3,7), ....) > >Reduce(union,l) -- View this message in context: http://www.nabble.com/How-to-union-the-elements-in-a-list--tp26100375p26100684.html Sent from the R help mailing list archive at Nabble.com.