similar to: creating NAs for some values only

Displaying 20 results from an estimated 10000 matches similar to: "creating NAs for some values only"

2006 Feb 20
3
Boxplot Help for Neophyte
R helpers I am getting to grips with R but came across a small problem today that I could not fix by myself. I have 3 text files, each with a single column of data. I read them in using: myData1<-scan("C:/Program Files/R/myData1.txt") myData2<-scan("C:/Program Files/R/myData2.txt") myData3<-scan("C:/Program Files/R/myData3.txt") I wanted to produce a
2012 Jun 06
3
problem about set operation and computation after split
hi, I met some problems in R, plz help me. 1. How to do a intersect operation among several groups in one list, without a loop statement? (I think It may be a list) create data: myData <- data.frame(product = c(1,2,3,1,2,3,1,2,2), year=c(2009,2009,2009,2010,2010,2010,2011,2011,2011),value=c(1104,608,606,1504,508,1312,900,1100,800)) mySplit<- split(myData,myData$year)
2012 May 15
4
reading data into R
Hi I am really new using R, so this is really a beginner stuff! I created a very small data set on excel and then converted it to .csv file. I am able to open the data on R using the command "read.table ("mydata1.csv", sep=",", header=T)" and it just works fine. But when I want to work on the data (e.g. calculate the mean of variable "X") R says
2013 Jan 10
1
Semi Parametric Bootstrap
Greetings to you all, I am performing a semi parametric bootstrap in R on a Gamma Distributed data and a Binomial distributed data. The main challenge am facing is the fact that the residual variance depends on the mean (if I am correct). I strongly feel that the script below may be wrong due to mean-variance relationship #####R code####### fit1s
2018 Mar 15
3
stats 'dist' euclidean distance calculation
Hello, I am working with a matrix of multilocus genotypes for ~180 individual snail samples, with substantial missing data. I am trying to calculate the pairwise genetic distance between individuals using the stats package 'dist' function, using euclidean distance. I took a subset of this dataset (3 samples x 3 loci) to test how euclidean distance is calculated: 3x3 subset used
2010 Nov 11
2
Kolmogorov Smirnov Test
I'm using ks.test (mydata, dnorm) on my data. I know some of my different variable samples (mydata1, mydata2, etc) must be normally distributed but the p value is always < 2.0^-16 (the 2.0 can change but not the exponent). I want to test mydata against a normal distribution. What could I be doing wrong? I tried instead using rnorm to create a normal distribution: y = rnorm
2012 Nov 24
1
Adding a new variable to each element of a list
Hello, I have a list of data with multiple elements, and each element in the list has multiple variables in it. Here's an example: ### Make the fake data dv <- c(1,3,4,2,2,3,2,5,6,3,4,4,3,5,6) subject <- factor(c("s1","s1","s1","s2","s2","s2","s3","s3","s3",
2009 Mar 27
4
A beginner's question
I am a new R-language user. I have set up a data frame "mydata",one of the colume of which is "skill". Now I want to select the observations whose "skill" value is equal to 1,by what command can I get it?
2012 Oct 20
2
Help with programming a tricky algorithm
Hi All, I'm a little stumped by the following problem. I've got a dataset with the following structure: idxy ix iy country (other variables) 1 1 1 c1 x1 2 1 2 c1 x2 3 1 3 c1 x3 . . . . . 3739 55 67 c7 x3739 3740 55 68 c7 x3740 where ix and
2011 Oct 17
2
Histogram for each ID value
I have a dataframe in the general format: chr1 0.5 chr1 0 chr1 0.75 chr2 0 chr2 0 chr3 1 chr3 1 chr3 0.5 chr7 0.75 chr9 1 chr9 1 chr22 0.5 chr22 0.5 where the first column is the chromosome location and the second column is some value. What I'd like to do is have a histogram created for each chr location (i.e. a separate histogram for chr1, chr2, chr3, chr7, chr9, and chr22). I am just
2008 Jan 08
1
retaining "POSIXct" formatting when using apply(muff, FUN=MAX) on POSIXct dataframe?
How do I retain "POSIXct" formatting when using apply, with FUN=max? #example: mydata <- rep(Sys.time(), 10) mydf <- data.frame(matrix(data=mydata, nrow=2, ncol=length(mydata) ) ) for(i in seq(mydf))class(mydf[[i]]) <- class(mydata) str(mydf) maxdates <- apply(mydf,2,max,na.rm=T) str(maxdates) #Why is the formattign now "chr", and not
2007 Nov 24
2
truncated fields with RODBC
I'm changing some functions from storing data in SQLite (using RSQLite) to storing it in PostgreSQL (using RODBC). When trying to store very long character fields I get the following message: > sqlSave(pg, Grids, rownames = FALSE, append = TRUE) Warning messages: 1: In odbcUpdate(channel, query, mydata, paramdata, test = test, verbose = verbose, : character data truncated in column
2005 Jul 19
1
S4 Dispatching
Is it possible for S4 to (continue) dispatch to a class created during dispatching? The code below doesn't work; is this not possible or have I ommitted something? Concept was to create a SEXP with R_AllocatePtr, give it a class attribute, and continue dispatch. Example code below omits multiple parameters that can be different types. Essentially, any parameter would be converted to an
2017 Nov 08
2
Help Converting Calendars
R-Help Trying to convert a Gregorian calendar dataset to a Persian calendar dataset. But I end up with a list and not sure what to do. For example ... dates <- c("2017-10-1","2017-10-2","2017-10-3") myData <- data.frame(dates) myData$dates <- as.Date(myData$dates, format = "%Y-%m-%d") > myData dates 1 2017-10-01 2 2017-10-02 3
2009 Jan 06
5
Using apply for two datasets
I can run one-sample t-test on an array, for example a matrix myData1, with the following apply(myData1, 2, t.test) Is there a similar fashion using apply() or something else to run 2-sample t-test with datasets from two groups, myData1 and myData2, without looping? TIA, Gang
2011 Feb 25
1
speed up process
Dear users, I have a double for loop that does exactly what I want, but is quite slow. It is not so much with this simplified example, but IRL it is slow. Can anyone help me improve it? The data and code for foo_reg() are available at the end of the email; I preferred going directly into the problematic part. Here is the code (I tried to simplify it but I cannot do it too much or else it
2017 Nov 08
0
Help Converting Calendars
How about > p_dates <- paste0(p.dates[[3]], "-", p.dates[[2]], "-", p.dates[[1]]) > myData$p_dates <- p_dates > print(myData, right=FALSE) dates p_dates 1 2017-10-01 1396-7-9 2 2017-10-02 1396-7-10 3 2017-10-03 1396-7-11 > str(myData) 'data.frame': 3 obs. of 2 variables: $ dates : Date, format: "2017-10-01"
2012 Jul 03
1
insert missing dates
Hello I have dataframes. mydata1 <-data.frame(value=c(15,20,25,30,45,50),dates=c("2005-05-25 07:00:00 ","2005-05-25 19:00:00","2005-06-25 07:00:00","2005-06-25 19:00:00 ","2005-07-25 07:00:00","2005-8-25 19:00:00")) or mydata2 <-data.frame(value=c(15,20,25,30,45,50),dates=c("2005-05-25 00:00:00 ","2005-05-25
2009 May 18
2
How do you save in R?
I know it sounds like a silly question but whenever i click on "save to file" it doesn't save. whenever i use the function attach(___) it doesn't work, and says object can not be found. i have a series of data (0,0,0,1,1) that i need to save, then i want to attach(...) it in another R window. Please help. Thanks -- View this message in context:
2007 Sep 26
2
date
Hello, I have got the following problem: > setwd("C:/temp") > library(xlsReadWrite) > MyData <- read.xls(file="Mappe1.xls", colNames = TRUE,dateTimeAs = "isodatetime") > attach(MyData) > MyData name value times 1 A1 2 2006-05-12 2 A2 3 2006-05-16 3 A3 1 2006-05-12 4 A4 4 2006-05-12 5 A5 2